3 years ago

A man stands on top of a cliff and shouts.

Physics

1 answer:

satela [25.4K]3 years ago

8 0

$\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x$

$\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1$

$\bf \to \: x = \frac{320}{2} m = 160m$

$\small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m$

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A mass m = 3.9 kg hangs from a massless string wrapped around a uniform cylinder with mass Mp = 10.53 and radius R= 0.96 m. The

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Answer:

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Formula for calculating Inertia can be expressed as:

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$I=5.265*(0.96)^2$

$I=4.852224$

I ≅ 4.85 kgm²

mg - T ma and RT = I ∝

T = $\frac{Ia}{R^2}$

$a = \frac{g}{1+\frac{I}{mR^2}}$

$a = \frac{9.8}{1+\frac{4.85}{3.9*(0.96)^2}}$

a = 4.1713 m/s²

Using the equation of motion

$v^2 = u^2+2as \\ \\ v^2 = 2as \\ \\ v = \sqrt{2*a*s} \\ \\ v= \sqrt{2*4.1713*7.56} \\ \\ v = 7.942 \ m/s$

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