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Akimi4 [234]
3 years ago
5

A man stands on top of a cliff and shouts.

Physics
1 answer:
satela [25.4K]3 years ago
8 0

\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x

\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

\bf \to \: x =  \frac{320}{2} m = 160m

\small \bf \: thus \: the \: distance \: between \: the \: cliffs \:  = 160m \times 2 = 320m

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Johnny walked to the other side of his building using the following steps: 10 meters North, 20 meters to the West, 40 meters Sou
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<u>Answer: </u>

  Distance traveled = 70 meters

  Displacement = 36.06 meters

<u>Explanation: </u>

 Let north be positive Y and east be positive X

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3 years ago
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Read 2 more answers
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
dedylja [7]

Answer:

Magnitude of net force will be 432.758 N  

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So net acceleration a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2

Now according to second law of motion

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3 0
3 years ago
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