How many newtons of force are required to move a 54.87 kg object with an acceleration of 9.8 m/s/s?
1 answer:
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Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
where v m/s is the final velocity, = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and
is the distance traveled:
To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.
By definition the change in speed is given by
Where,
x= distance
final velocity
initial velocity
a = acceleration
On the other hand we know that the flow of a fluid is given by
Where,
A = Area
v = Velocity
PART A )
Applying this equation to the previously given values we have to
Therefore the velocity of the water leaving the hole is 17.48m/s
PART B )
In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,
The diameter is 2 times the radius, then is m or 1.91mm
<em>Note: The rate flow was converted from minutes to seconds.</em>