A ball is dropped from a roof of a building and strikes the ground in 3 seconds. If a second ball is thrown horizontally from th
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Answer:
The acceleration of the ball's center of mass = 2.94 m/s²
Explanation:
The speed of the ball at the base of the ramp, v = 2.63 m/s
Mass of the ball = 1.75 kg
Radius of the ball, R = 40 cm = 0.4 m
In this motion, potential energy due to the height of the ball is converted to linear angular kinetic energy
Based on the law of energy conservation
Potential energy = Linear KE + angular KE
KE = kinetic Energy
Linear KE = 0.5 mv²
Linear KE = 0.5 * 1.75 * 2.63²
Linear KE = 6.052 J
Angular KE = 0.5 Iω²
I = 2/ 3 MR² = 0.667 * 1.75 * 0.4²
I = 0.187 N.s
ω = V/R = 2.63/0.4
ω = 6.575 Rad/s
Angular KE = 0.5 * 0.187 * 6.575²
Angular KE = 4.04 J
PE = mgh = 1.75 * 9.8 * h = 17.15h
Using the law of energy conservation
17.15h = 6.052 + 4.04
h = 10.092/17.15
h = 0.589 m
Using the equation of motion
Answer:
<u>18000 J</u> is the work can do by the motor.
Explanation:
If an electric motor works for 12 seconds and the power output is 1.5 KW = 1500 Watts we need to find how much work can an electric motor does.
We know that,
“Power” is defined as the “rate” of doing “work”, the “energy” transferred or converted per unit time. Mathematically,
Where, units of power is “Watt”, units of work is “Joule” and time in “seconds”.
Substitute the given values to find work
1500 × 12 = work
Work = 18000 Joules
Therefore, work can done by an electric motor is <u>18000 J</u>.