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disa [49]
2 years ago
11

How much do you do when you stand by carrying 50 kg load bricks? write the reason​

Physics
1 answer:
yanalaym [24]2 years ago
6 0

Answer:

No work is done yet

Explanation:

Given data

Weight of the load=50kg

Distance= 0 meter ------------Standing on one point

Normally, work is said to be done when we apply a force/carry a load through a distance, since the person is standing and not moving through a distance, no work is done

Hence

Work done= 50*0= 0 joules

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Julio blows air across his hot bowl of soup. The tiny ripples he creates are similar to _____.
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The tiny ripples on the soup are not only similar to wind-generated
waves ... they ARE wind-generated waves.  This is a big part of the
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3 years ago
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Is it possible that a speed of 254 and a speed of 100 could be the same speed?
EastWind [94]
Not if both speeds are in the same units.

However, if the 254 is 'centimeters per time' and the 100 is 'inches per time',
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4 0
3 years ago
You and a friend frequently play a trombone duet in a jazz band. During such performances it is critical that the two instrument
Rashid [163]

Answer:

f₂ = 468.67 Hz

Explanation:

A beat is a sudden increase and decrease of sound. The beats are produced through the interference of two sound waves of slightly different frequencies. Now we have the following data:

The higher frequency tone = f₁ = 470 Hz

No. of beats = n = 4 beats

Time period = t = 3 s

The lower frequency note = Frequency of Friend's Trombone = f₂ = ?

Beat Frequency = fb

So, the formula for beats per second or beat frequency is given as:

fb = n/t

fb = 4 beats/ 3 s

fb = 1.33 Hz

Another formula for beat frequency is:

fb = f₁ - f₂

f₂ =  f₁ - fb

f₂ = 470 Hz - 1.33 Hz

<u>f₂ = 468.67 Hz</u>

6 0
2 years ago
What game most represents a wave
Julli [10]

Answer:

tipping over dominoes

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6 0
3 years ago
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A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
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Answer:

62.06 g/mol

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We are given that a solution containing 10 g of an unknown liquid and 90 g

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Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

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M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

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