Answer:
Explanation:
Let the intensity of unpolarised light be I₀ . After passing through the first polarising filter , the intensity is I₀ / 2 .
After second filter , the intensity will be I₀ / 2 x cos²45 = I₀ / 4
After third filter , the intensity will be I₀ / 4 x cos²45 = I₀ / 8 .
So,
1 / 8 the of initial light passes through the last filter .
u might be right
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Answer:
<em>the ball travels a distance of 8.84 m</em>
Explanation:
Range: Range is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again.
R = (U²sin2∅)/g.............................. Equation 1
Where R = range, U = initial velocity, ∅ = angle of projection, g = acceleration due to gravity.
<em>Given: U = 10 m/s, ∅ = 60°</em>
<em>Constant: g = 9.8 m/s²</em>
Substituting these values into equation 1
R = [10²×sin(2×60)]/9.8
R = (100sin120)/9.8
R = 100×0.8660/9.8
R = 86.60/9.8
R = 8.84 m
<em>Therefore the ball travels a distance of 8.84 m</em>
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
where f, for a concave mirror, is taken to be positive.
Re-arranging the formula we get:
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
Answer:the line away from the spacecraft should be straight down (perpendicular to it). Label this M. This is the force of the moon on the spacecraft. A minuscule line upward from the moon towards the spacecraft shows the force of the spacecraft on the moon. Should be directly below the spacecraft and pointed straight up at it.
Explanation:
