After 6 years the investment is $5555.88
Step-by-step explanation:
A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?
The formula used to find future value is:
![A(t)=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%28t%29%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
where A(t) = Accumulated amount
P = Principal Amount
r = annual rate
t= time
n= compounding periods per year
We are given:
P = $3600
r = 7.5 %
t = 6
n = 1
Putting values in formula:
![A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88](https://tex.z-dn.net/?f=A%28t%29%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D%5C%5CA%28t%29%3D3600%281%2B%5Cfrac%7B0.075%7D%7B1%7D%29%5E%7B6%2A1%7D%5C%5CA%28t%29%3D3600%28%5Cfrac%7B1.075%7D%7B1%7D%29%5E6%5C%5CA%28t%29%3D3600%281.075%29%5E6%5C%5CA%28t%29%3D3600%281.543%29%5C%5CA%28t%29%3D5555.88)
So, After 6 years the investment is $5555.88
Keywords: Compound Interest formula
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So, there will be 40 green cars. if we want the ratio to be 1:3, we will need there to b three times as many silver cars as green cars: 40*3=120.
we already have 20 silver, so we need to add 120-20, that is 100 silver cars!
![\frac{12 - 10}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%20-%2010%7D%7B10%7D%20)
Thats what you would use, so now 2/10 is .2 When you divide so you move the decimal so 20%
The percent increase is 20%
One coordinate that is 7 units away from (2,-7) is (2,0). (2,0) is 7 units to the right of (2,-7)
Another coordinate is (9,-7). This one also works.
Answer: To solve these types of questions what I always do is get a protractor if you have one and put it up against to where the dot is in the middle of the empty hole and then get a ruler or a pencil and make the line keep going to see what angle. In this case your answer is 65% I think.