Answer
given,
wavelength of the red light,λ = 687 nm
wavelength of the yellow light = 582 nm
Frequency of red light
=
=
= 4.36 x 10¹⁴ Hz
frequency of the yellow light
=
= 5.15 x 10¹⁴ Hz
speed of the car
v_r is the required speed.
v_r = 0.19 c
v_r = 0.19 x 3 x 10⁸ =5.7 x 10⁷ m/s
1 m/s = 2.23694 mile/hr
v_r = 1.27 x 10⁸ mile/hr
if the light is actually yellow
f₀ = 5.15 x 10¹⁴ Hz
f = 6.13 x 10¹⁴ Hz
wavelength corresponding to this frequency is wavelength = 493.2 nm
hence, the color corresponding to this wavelength is Green.
Answer:
Explanation:
initial velocity u = 0
final velocity v = 11.3 m /s
distance covered s = 12.8 m
v² = u² + 2 a s
11.3² = 0 + 2 x a x 12.8
a = 4.99 m /s²
again ,
v = u + a t
11.3 = 0 + 4.99 t
t = 2.26 s .
Rest of the sprint will be covered with uniform velocity .
Distance covered = 100 - 12.8 = 87.2 m
speed = 11.3 m /s
time taken = 87.2 / 11.3 = 7.7 s
Total time of 100 m sprint = 7.7 + 2.26 = 9.96 m .
b )
Let the time taken to reach the top speed be t .
acceleration a = 11.3 / t
distance covered s = 1/2 a t²
= .5 x (11.3 / t) x t²
= 5.65 t
Rest of the distance = 100 - 5.65 t
time taken to cover rest of the distance = (100 - 5.65 t ) / 11.3
Total time = (100 - 5.65 t / 11.3 ) + t = 9.75
100 - 5.65 t + 11.3 t = 11.3 x 9.75
100 + 5.65 t = 110.175
5.65 t = 10.175
t = 1.8
acceleration a = 11.3 / t
= 11.3 / 1.8
= 6.278 m /s²
distance covered in 1.8 s
s = 1/2 a t²
= .5 x 6.278 x 1.8²
= 10.17 m .
1). No. In a series circuit, the current leaving the battery is the same as the current arriving back at the battery at the other end of the circuit, and the same as the current at every point around the circuit.
2). True.
3). True
4). True
5). No. See #3.
6). No. See #2.
The pressure dropped by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Using the attached map below, in the morning of November 9, the pressure situated at the storm's center = 1000 MB isobar located at the center.
Meanwhile, on November 11, 0000z the pressure situated at the storm's center = 976 MB isobar
The difference in this pressure is regarded as the pressure drop in the storm's center and it is determined as follows;
= 1000 MB - 976 MB
= 24 MB
Therefore, we can conclude that the pressure drop by 24 MB in the storm's center from November 9, 1200z, until November 11, 0000z.
Learn more about pressure drop in an isobaric process here:
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