Question

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:

Answer 1

Answer:$3.01\times 10^{3}J$

Explanation:

Let $T$ be the temperature in kelvin.

Let $KE$ be the average kinetic energy.

Let $n$ be the number of moles.

Let $R$ be the universal gas constant.

As we know,

$KE=\dfrac{3}{2}nRT$

Given,

$n=1\\T=273-32=241K$

we know that $R=8.314JK^{-1}mol^{-1}$

So,$KE=\frac{3}{2} \times 1\times 8.314\times 241=3005.5J$=$3.01\times 10^{3}J$