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Alexxandr [17]
3 years ago
10

How many grams of Magnesium Chloride (molar mass = 95.2 g/mole) will be needed to make 6.0 L of a 2.5 M MgCl2 solution?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:

1428 g

Explanation:

2.5 M = 2.5 mol/L

2.5mol/L*6.0 L = 15 mol MgCl2.

Molar mass (MgCl2) = 24.3 g/mol+(2*35.5 g/mol)=95.2 g/mol

15 mol * 95.2 g/mol = 1428 g

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If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa,
Feliz [49]

Answer: The volume of the balloon at the center of the typhoon is 41.7L.

Note: The complete question is given below;

If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?

The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.

Explanation:

Since no temperature changes were given, it is assumed to be constant. Therefore, Boyle's law which describes the relationship between pressure and volume is used to determine the new volume at the center of Typhoon Odessa. Mathematically, Boyle's law states that; P1V1 = P2V2

Assuming 1atm = 1 bar, 1mbar = 0.001atm, 40mbar = 0.040atm

P1 = 1.0atm, V1 = 40.0L, P2 = 1atm - 0.040atm = 0.960atm, V2 = ?

Using P1V1 = P2V2

V2 = P1V1/P2

V2 = 1.0 * 40.0 / 0.96

V2 = 41.67L

Therefore, the volume of the balloon at the center of the typhoon is 41.7L.

5 0
3 years ago
Inferential statistics allows a researcher to make inferences about a specific population based on data taken from a sample. Ple
son4ous [18]

Answer:

The correct answer is "True".

Explanation:

Inferential statistics derives from statistics that comprise the methods and procedures by which, using induction, it determines the properties of a statistical population from a sample of this population. The objective of this type of statistics is to obtain useful conclusions to be able to make deductions on a population, based on the information of the sample taken from it.

Have a nice day!

5 0
3 years ago
Read 2 more answers
What ion must be present for a compound to be considered a base?
Alexeev081 [22]
It is OH- (hydroxide ion)
4 0
4 years ago
Write balanced net ionic equations and the corresponding equilibrium equations for the stepwise dissociation of the triprotic ac
Elza [17]

Answer:

H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1

H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2

HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3

Explanation:

Hello!

In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:

H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1

H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2

HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3

Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:

Ka1 > Ka2 > Ka3

Best regards!

3 0
3 years ago
#9 answer with explanation
Slav-nsk [51]

Answer:

A.  6.0 mol H₂O

Explanation:

3 mol O₂ x  \frac{2 mol H2O}{1 mol O2} = 6 mol H₂O

6 0
3 years ago
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