The graph below shows the relationship between speed and time for two objects, A and B. Compare with the acceleration of object
B, the acceleration of object A is
A. Greater
B. The same
C. Lesser
D. One-third as less
A. Greater
B. The same
C. Lesser
D. One-third as less
2 answers:
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Answer:
Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf
Explanation:
First we will find the acceleration of pickup truck.
As, the acceleration is uniform, therefore we can use Newton's third equation of motion:
2as =
First convert speed into ft/sec
1 mile/hr = 1.47 ft/sec
therefore,
37 mile/hr = 37 x 1.47 ft/sec
37 mile/hr = 54.39 ft/sec
with initial speed 0 ft/sec (starting from rest), using in equation of motion:
a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)
a = 6.88 ft/sec²
Now, the total shear force will be given by Newton's second law of motion:
F = ma
F = (460 lbm +72 lbm)(6.88 ft/sec²)
F = 3660 lbf
Now for the max shear force in each of the two pegs we divide total fore by 2:
Force in each peg = F/2 = (3660 lbf)/2
<u>Force in each peg = 1830 lbf</u>
Answer:
check image
Explanation:
For any question related to newons law of motion first draw the free body diagram(FBD),
let here North direction is along +Y and South direction is along -Y
similarly East direction is towards +X and west direction is towards -X
now it is given that
first it moves 235 km north
then it moves back 126 km south
then again he moves north
now the total displacement is given as
so final displacement of train is 154 km North