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lys-0071 [83]
3 years ago
7

The graph below shows the relationship between speed and time for two objects, A and B. Compare with the acceleration of object

B, the acceleration of object A is
A. Greater
B. The same
C. Lesser
D. One-third as less

Physics
2 answers:
Fiesta28 [93]3 years ago
7 0
Answer is C: Greater
kolbaska11 [484]3 years ago
5 0

Answer:

A) greater

Explanation:

acceleration is calculated by dividing velocity over time..so by calculating, you find acceleration of A is greater than that of B

You might be interested in
How does the force of gravity exerted
givi [52]

The two forces of gravity are equal

Explanation:

We can answer this question by applying Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

In this problem, we can identify the Sun as object A and the Earth as object B. This means that the force of gravity exerted by the Sun on the Earth is the action, while the force of gravity exerted by the Earth on the Sun is the reaction: according to Newton's third law, these two forces are equal and opposite.

Therefore, the two forces of gravity are equal in magnitude, which is given by:

F=\frac{GMm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the Earth

r is the separation between the Earth and the Sun

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

8 0
3 years ago
The capitary action of water is caused the cohesion of water molecules to different types of molecules and the adhesion of water
s344n2d4d5 [400]

Answer:

This is True

Explanation:

I just did this exact unit in bio last week I hope this helps ;)

5 0
3 years ago
A 2.3 kg particle-like object moves in a plane with velocity components vx = 40 m/s and vy = 75 m/s as it passes through the poi
Sonbull [250]

Answer:

(a) \overrightarrow{L}=885.5\widehat{k}

(b) \overrightarrow{L}=1046.5\widehat{k}

Explanation:

mass, m = 2.3 kg

vx = 40 m/s

vy = 75 m/s

(a) Angular momentum is given by

\overrightarrow{L}=\overrightarrow{r}\times \overrightarrow{p}

Where, p is the linear momentum and r is the position vector about which the angular momentum is calculated.

Here, \overrightarrow{r}=3\widehat{i}-4\widehat{j}

\overrightarrow{p}=m\overrightarrow{v}

\overrightarrow{p}=2.3\left ( 40\widehat{i}+75\widehat{j} \right )

\overrightarrow{p}= 92\widehat{i}+172.5\widehat{j}

So, the angular momentum

\overrightarrow{L}=\left ( 3\widehat{i}-4\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )

\overrightarrow{L}=885.5\widehat{k}

(b) Here, \overrightarrow{r}=(3+2)\widehat{i}+(-4+2)\widehat{j}

\overrightarrow{r}=5\widehat{i}-2\widehat{j}

\overrightarrow{L}=\left ( 5\widehat{i}-2\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )

\overrightarrow{L}=1046.5\widehat{k}

6 0
3 years ago
The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr
Mandarinka [93]

Answer:

The magnitude of minimum potential difference is 1800 V

Explanation:

Given:

Electric field E = 3 \times 10^{6} \frac{V}{m}

Gap between electrodes d = 0.060 \times 10^{-2} m

For finding the minimum potential difference,

  \Delta V = E \times d

  \Delta V = 3 \times 10^{6} \times 0.060 \times 10^{-2}

  \Delta V = 1800 V

Therefore, the magnitude of minimum potential difference is 1800 V

8 0
3 years ago
A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.
nikdorinn [45]

Answer:

a

 \frac{d \phi_{E}}{dt}  =1.1977 *10^{10} \  V\cdot m/s

b

 I = 0.106 \  A

Explanation:

From the question we are told that

  The current is  I =  0.106 \  A

   The length of one side of the square a = 4.60 \  cm = 0.046 \  m

    The separation between the plate is  d = 4.0 mm  = 0.004 \ m

Generally electric flux is mathematically represented as

       \phi_E = \frac{Q}{\epsilon_o}

differentiating both sides with respect to t is  

       \frac{d \phi_{E}}{dt}  = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}

=>     \frac{d \phi_{E}}{dt}  = \frac{1}{\epsilon_o} *I

Here \epsilon_o is the permitivity of free space with value  

        \epsilon _o  =  8.85*10^{-12} C/(V \cdot m)

=>   \frac{d \phi_{E}}{dt}  = \frac{0.106}{8.85*10^{-12}}

=>   \frac{d \phi_{E}}{dt}  =1.1977 *10^{10} \  V\cdot m/s

Generally the displacement current between the plates in A

    I = 8.85*10^{-12} * 1.1977 *10^{10}

=>  I = 0.106 \  A

 

3 0
2 years ago
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