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nadya68 [22]
3 years ago
11

John measures the mass of a cup of chocolate milk and a glass of orange Juice. He places both containers on a balance scale. He

observes that the scales tips fower towards the cup of chocolate
milk. He concludes that the chocolate milk has a greater mass. What statement best describes the error in John's measurement? (2 points)
Only solids have mass so comparing the mass of two liquids is not possible.
John can only compare the mass of two liquids that are the same.
John has to pour each liquid into a container with the same mass and then compare them
The liquids need to be poured into the same container
accurately compare them
Chemistry
1 answer:
mylen [45]3 years ago
5 0

Answer:

b. John has to pour each liquid into a container with the same mass and then compare them

would be the correct answer.  Hope this helps!

Explanation:

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An atom can be neutral when there a same amount of protons and electrons
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Why do we see different phases of the moon.
nadya68 [22]

Answer:

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Explanation:

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3 years ago
Read 2 more answers
A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the
nalin [4]

Answer:

P \approx 225atm

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 P=\frac{nRT}{V}

 P=\frac{3.20*0.08206*300}{350*10^{-3}}

 P=225.079atm

 P \approx 225atm

4 0
3 years ago
Which of the following is not a physical property of a liquid? indefinite volume indefinite shape definite mass
Elanso [62]
Definitely definite mass because liquids can take on any shape and can have different volumes.
3 0
3 years ago
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What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K
vlada-n [284]

Answer:

=1.666 liters

Explanation:

1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.

0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1

=11.2 liters.

Standard pressure= 1 atmosphere (Atm)

Standard temperature = 273.15 Kelvin

According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂

Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.

Therefore P₂ =P₁V₁T₂/T₁V₂

Substituting for the values we get:

P₂= (1 atm× 11.2L ×203K)/ (273K×5L)

=1.666 atm

5 0
3 years ago
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