V1/T1 = V2/T2
Substitute the value use ratio and proportion. Use calculator.
V1 = (V2 x T1) / T2
1 is initial, 2 is final
Answer : The wavelength is 
Solution : Given,
frequency = 29.2 Hz
Formula used :
where,
= frequency
= wavelength
c = speed of light = 
Now put all the given values in this formula, we get the wavelength.
Therefore, the wavelength is
Answer:
Boiling point for the solution is 100.237°C
Explanation:
We must apply colligative property of boiling point elevation
T° boiling solution - T° boiling pure solvent = Kb . m
m = molalilty (a given data)
Kb = Ebulloscopic constant (a given data)
We know that water boils at 100°C so let's replace the information in the formula.
T° boiling solution - 100°C = 0.512 °C/m . 0.464 m
T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C
Answer: 292.54g of Ag
Explanation:
Cu + 2AgNO3 →Cu(NO3)2 + 2 Ag
mass conc. Of Ag = n x molar Mass
Mass conc. Of Ag = 2 x 108 = 216g
From the equation,
63.5g of Cu produced 216g of Ag
Therefore, 86g of Cu will produce Xg of Ag. i.e
Xg of Ag = (86 x 216)/63.5 = 292.54g
<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>
Explanation:
Atom
It is a smallest particle which cant exist independently.
According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.
These subatomic particles have marked properties .
Proton
- It was discovered by E.Goldstein .
- It is positively charged particle
- It is present in nucleus .
- Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms
Neutron
- It was discovered by E.chadwick .
- It is neutral
- It is present inside the nucleus .
- It's mass is equal to 1.674927471×10⁻²⁷ kg
Electron
- It was discovered by J.J Thomson .
- It has negative charge .
- It's mass is equal to 9.10938356 × 10⁻³¹ kilograms
- It is present outside the nucleus in shells .
