Hello there,
Your correct answer would be "<span>the energy of a photon".
Hope this helps.
~Hottwizzlers
</span>
<u>Answer:</u> The expression of 
is written below.
<u>Explanation:</u>
We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.
It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.
The chemical equation for the reaction of trimethylamine in water follows:
The expression of for above equation follows:
![K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%7D)
Hence, the expression of is written above.
Answer:Answer: (B) Archaebacteria
Explanation:
Explanation: Archaebacteria, like all prokaryotes, have no membrane bound organelles. This means that the archaebacteria are without nuclei, mitochondria, endoplasmic reticula, lysosomes, Golgi complexes, or chloroplasts. Because these organisms have no nucleus, the genetic material floats freely in the cytoplasm
Answer:
Single-celled organisms use cell division as their method of reproduction. Cell Division and Growth: A sea urchin begins life as a single cell that (a) divides to form two cells, visible by scanning electron microscopy.
Explanation:
Los organismos unicelulares utilizan la división celular como método de reproducción. División y crecimiento celular: un erizo de mar comienza su vida como una sola célula que (a) se divide para formar dos células, visibles mediante microscopía electrónica de barrido.
Answer is: f<span>ormula for the hydrated compound is CuSO</span>₄·3H₂O.
ω(H₂O) = 25,3% = 0,253.
ω(CuSO₄) = 100% - 25,3%.
ω(CuSO₄) = 74,7% = 0,747.
ω(H₂O) : M(H₂O) = ω(CuSO₄) : M(CuSO₄).
0,253 : M(H₂O) = 0,747 : 159,6 g/mol.
M(H₂O) = (0,253 · 159,6 g/mol) ÷ 0,747.
M(H₂O) = 54 g/mol.
N(H₂O) = 54 g/mol ÷ 18 g/mol.
N(H₂O) = 3.
