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Galina-37 [17]
3 years ago
7

How many molecules of H2O and O2 is present in 8.5g of H2O?​

Chemistry
1 answer:
Igoryamba3 years ago
3 0

Answer:

2.8 x 10²³ molecules H₂O

1.4 x 10²³ molecules O₂

Explanation:

First, you will need the balanced chemical equation for the formation of water:

2H₂ + O₂ -> 2H₂O

This will help in determining the mole ratios between water and oxygen, which we will need later.

Let's first calculate the number of H₂O (water) molecules. This will require stoichiometry. We are also given the mass, so we must convert mass into moles, then moles into molecules. mass -> moles -> molecules

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (6.02 x 10²³ molecules H₂O/1 mol H₂O) = 2.8404 x 10²³ molecules H₂O

Rounded to 2 significant digits: 2.8 x 10²³ molecules H₂O

Now, to find the molecules of water, we can begin with the same stoichiometric equation, but before we convert to molecules, we will have to convert moles of water to moles of oxygen. This is where we will use the mole ratio of water to oxygen we got from the balanced chemical equation earlier. 2H₂O:1O₂

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (1 mol O₂/2 mol H₂O) x (6.02 x 10²³ molecules O₂/1 mol O₂) = 1.4202 x 10²³ molecules O₂

Rounded to 2 significant digits: 1.4 x 10²³ molecules O₂

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7 0
3 years ago
Strontium carbonate + sulphuric acid, chemical equation​
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<h3>Answer:</h3>

SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

<h3>Explanation:</h3>

We are required to complete the chemical equation given;

strontium carbonate + sulfuric acid → ??

  • We know that, carbonates reacts with acids to form a salt, water and carbon dioxide.
  • Strontium carbonate reacts with sulfuric acid to form strontium sulfate, water and carbon dioxide.
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SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

  • The equation is balanced as the number of atoms of each element are equal on both sides of the equation.
7 0
3 years ago
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