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son4ous [18]
3 years ago
7

Simplify 7p +20-13q-4q-18+6p a 13p + 17q-2 b 13p-17q+2 c3q+38 d 3q-6

Mathematics
2 answers:
AleksAgata [21]3 years ago
3 0
The answer is most likely B
Alika [10]3 years ago
3 0
I got 13p+2-17q I think your best choice would be B
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100 POINTS!!!!! WILL GIVE BRAINLIEST!!!!!!! <br> Show that: (a + bi)^2 = (a + b)(a − b) + 2abi
inna [77]

Step-by-step explanation:

(a+bi)2

=a2 +2abi +b2i2

=a2 +2abi + b2. (-1)

=a2 -b2 +2abi

Answer = (a+b(a-b) +2abi

8 0
2 years ago
How to solve a system of three equations with substitution
zloy xaker [14]

Answer:

Usually there are the variables x y z but it doesn't matter what they are.

Step-by-step explanation:

First choose your first variable to solve. Find x by putting all the numbers and variables to one side.

once you found x substitute the answer for x in all the equations. Next find y and substitute your answer in all the equations again.

Once you have solved 2 variables then you are able to solve z.  

If you have questions please feel free to ask in the comments below.

4 0
3 years ago
Which one is the even number:<br> 116,318,162,230,180,155
Blababa [14]

Answer:

they are all even numbers except for 155

Step-by-step explanation:

8 0
2 years ago
A new truck sells for $29,000 and depreciates 12% each year. Find the value of the truck after 10 years.
ozzi

Answer:

according to the question value got less 12% each year

first of all the 12% of 29000$ = 29000÷100×12= 3480 $

in one year truck value deprecates 3480$

in 10 years it will 3480$×10 =34800$

now truck cost will be = 29000-34800$= -5000$

5 0
2 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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