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2 years ago

Simplify 7p +20-13q-4q-18+6p a 13p + 17q-2 b 13p-17q+2 c3q+38 d 3q-6

Mathematics

2 answers:

AleksAgata [21]2 years ago

3 0

The answer is most likely B

Alika [10]2 years ago

3 0

I got 13p+2-17q I think your best choice would be B

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sergeinik [125]

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Given the function
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2 years ago

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Look at this cylinder:

Sedbober [7]

Height=h=8cm
Radius=r=4cm

We know

$\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2$

Now

New Radius=2(4)=8cm
New Height=2(8)=16cm

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}$

Hence our correct option is Option C

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2 years ago

Find the product.<br> (n^3)^2 * (n^5)^4

Brums [2.3K]

Hi

(n^3)^2 × (n^5)^4 = n^6 × n^20 = n^26

<span>Answer: n^26</span>

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3 years ago

What is 1+18636-653736{763738-6639+

sertanlavr [38]

Answer:

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Step-by-step explanation:

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3 years ago