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1 year ago

The position of a particle is given by s = 0.27t

Engineering

1 answer:

Natali [406]1 year ago

8 0

Sorry bro people do this22.2 pls

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Consider a vortex filament of strength in the shape of a closed circular loop of radius R. Obtain an expression for the velocity

zysi [14]

Answer:

v = T/(2R)

Explanation:

Given

R = radius

T = strength

From Biot - Savart Law

dv = (T/4π)* (dl x r)/r³

Velocity induced at center

v = ∫ (T/4π)* (dl x r)/r³

⇒ v = ∫ (T/4π)* (dl x R)/R³ (k) k: unit vector perpendicular to plane of loop

⇒ v = (T/4π)(1/R²) ∫ dl

If l ∈ (0, 2πR)

⇒ v = (T/4π)(1/R²)(2πR) (k) ⇒ v = T/(2R) (k)

3 0

3 years ago

An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions. If the

xenn [34]

Answer:C 0.12 V

Explanation:

Given

Concentration of $Fe^{2+} M_1=0.40 M$

Concentration of $Ni^{2+} M_2=0.002 M$

Standard Potential for Ni and Fe are $V_2=-0.25 V$ and $V_1=-0.44 V$

$\Delta V=V_2-V_1-\frac{0.0592}{2}\log (\frac{M_1}{M_2})$

$\Delta V=-0.25-(-0.44)-\frac{0.0592}{2}\log (\frac{0.4}{0.002})$

$\Delta V=0.12\ V$

7 0

3 years ago

1 A power transmission includes a belt drive, a chain drive and a gear drive. Which of the following is the best arrangement bet

Setler79 [48]

Answer:d

Explanation:

(d) chain drive belt drive gear drive

3 0

2 years ago

g Consider a thin opaque, horizontal plate with an electrical heater on its backside. The front end is exposed to ambient air th

xxTIMURxx [149]

Answer:

The electrical power is 96.5 W/m^2

Explanation:

The energy balance is:

Ein-Eout=0

$qe+\alpha sGs+\alpha skyGsky-EEb(Ts)-qc=0$

if:

Gsky=oTsky^4

Eb=oTs^4

qc=h(Ts-Tα)

$\alpha s=\frac{\int\limits^\alpha _0 {\alpha l Gl} \, dl }{\int\limits^\alpha _0 {Gl} \, dl }$

$\alpha s=\frac{\int\limits^\alpha _0 {\alpha lEl(l,5800 } \, dl }{\int\limits^\alpha _0 {El(l,5800)} \, dl }$

if Gl≈El(l,5800)

$\alpha s=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))$

lt= 2*5800=11600 um-K, at this value, F=0.941

$\alpha s=(0.8*0.941)+0.3(1-0.941)=0.77$

The hemispherical emissivity is equal to:

$E=(1-0.2)F(0-2)+(1-0.7)(1-F(0-2))$

lt=2*333=666 K, at this value, F=0

$E=0+(1-0.7)(1)=0.3$

The hemispherical absorptivity is equal to:

$qe=EoTs^{4}+h(Ts-T\alpha )-\alpha sGs-\alpha oTsky^{4}=(0.3*5.67x10^{-8}*333^{4})+10(60-20)-(0.77-600)-(0.3*5.67x10^{-8}*233^{4})=96.5 W/m^{2}$

3 0

3 years ago

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allsm [11]

Answer:

wow

Explanation:

that's so cute!!!!!!!!

3 0

2 years ago