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labwork [276]
2 years ago
6

A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)

Engineering
1 answer:
LenaWriter [7]2 years ago
8 0

9514 1404 393

Answer:

  see below

Explanation:

We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.

Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.

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In javaWrite a program that simulates flipping a coin to make decisions. The input is how many decisions are needed, and the out
Pavel [41]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

import java.util.*;

public class FlipCoin

{

public static void main(String[] args)

{

// Declare Scanner

Scanner input = new Scanner (System.in);

int flips;

// Prompt to enter number of toss or flips

System.out.print("Number of Flips: ");

flips = input.nextInt();

if (flips > 0)

{

HeadsOrTails();

}

}

}

public static String HeadsOrTails(Random rand)

{

// Simulate the coin tosses.

for (int count = 0; count < flips; count++)

{

rand = new Random();

if (rand.nextInt(2) == 0) {

System.out.println("Tails"); }

else {

System.out.println("Heads"); }

rand = 0;

}

}

7 0
3 years ago
2 Blocks 1 and 2 rest on rough surfaces with coefficient of frictions ¢1 and ¢2 respectively. The blocks
Amiraneli [1.4K]

Answer:

  • 100N
  • 25N

Explanation:

a) On the verge of tipping over, reaction acts at the corner A

When slippage occurs,

Block moves w/ const. velocity  equilibrium

Three-force member: reaction at A must pass through B

tan b/2h, h b/ 2 θ µ = = ∴= k k ( µ )

b) When slippage occurs,

Block moves w/ const. velocity  equilibrium

Three-force member: reaction at C must pass through G

k tanθ µ =

tan x/ H/2 , x H/2

4 0
3 years ago
A cone-shaped part is to be fabricated using stereolithography. The radius of the cone at its base = 35 mm, and its height = 50
iren [92.7K]

Explanation:

volume = πR²h/3

= πx35²x50/3

= 192325/3

= 64166.725

number of layers n = 50mm/0.05

n = 1000layers

average volume = 64166.725/1000

= 64.167mm³

average area = 64.167/0.05

= 1283.34mm²

average time = 1283.34/900mm x 0.22

= 6.48

6.48 + 15 seconds

= 21.48 seconds

time required = 1000x21.48

= 21480 seconds

convert to minutes

21480/60

= 358 minutes

21480/3600

= 5.967 hours

8 0
3 years ago
Click this link to view O*NET’s Work Activities section for Graphic Designers. Note that common activities are listed toward the
bixtya [17]
I can’t click on the link sorry man
8 0
2 years ago
Read 2 more answers
Q1. A truck traveling at 40 mph is approaching a stop sign. At time ????0 and at a distance of 80ft, the truck begins to slow do
densk [106]

Answer:

The truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.

Explanation:

The distance that the truck starts slowing down = 80 ft from the stop sign

Using equations of motion, we can calculate the distance it will take the truck to stop, then check of it is less than or more than 80 ft.

u = initial velocity of the truck = 40 mph = 58.667 ft/s

v = final velocity of the truck = 0 ft/s (since it comes to a stop eventually)

x = horizontal distance covered during the deceleration

a = Deceleration = -12 ft/s² (it'll have a negative sign, since it is negative acceleration

v² = u² + 2ax

0² = 58.667² + 2(-12)(x)

24x = 3441.816889

x = 143.41 ft

143.41 ft > 80 ft; hence, the truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.

7 0
3 years ago
Read 2 more answers
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