A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)
1 answer:
9514 1404 393
Answer:
see below
Explanation:
We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.
Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.
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Answer:
the difference in pressure between the inside and outside of the droplets is 538 Pa
Explanation:
given data
temperature = 68 °F
average diameter = 200 µm
to find out
what is the difference in pressure between the inside and outside of the droplets
solution
we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is
σ = 2.69 × N/m
so average radius = = 100 µm = 100 ×
m
now here we know relation between pressure difference and surface tension
so we can derive difference pressure as
2π×σ×r = Δp×π×r² .....................1
here r is radius and Δp pressure difference and σ surface tension
Δp =
put here value
Δp =
Δp = 538
so the difference in pressure between the inside and outside of the droplets is 538 Pa