A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)
1 answer:
9514 1404 393
Answer:
see below
Explanation:
We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.
Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.
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Answer:
a
The rate of radiation of the energy is
b
The irradiation is
c
The amount of energy absorbed is
d
The oak Tree would catch fire because the temperature of the blast(7200 K) is higher than the flammability limit (650 K) of the oak tree and secondly the thickness is very small
Explanation:
From the question we are told that
The temperature is
The diameter of the ball is
Hence the radius =
The total energy radiated can be mathematically represented as
Where is the Stefan-Boltzmann constant
A is the area of a sphere =
Substituting values we have
Now the state of the energy is mathematically represented as
A sketch illustrating the b part of the question is shown on the first uploaded image
looking at the height at which the blast occurs(16km) as compared to the height of the wall we notice that the height of the wall is negligibly small
from the diagram x can be calculated as follows
This value of x represents the radius of the blast(assuming it is spherical ) when it is at that wall
Now the irradiation G is mathematically represented as
Here r = 43.0813 Km = 43.0813 × 1000 = 43081.3 m
Generally the amount of energy absorbed can be mathematically represented as
Where t is the time taken
Therefore
Answer:
the required diameter is 0.344 m
Explanation:
given data:
flow is laminar
flow of carbon dioxide Q = 0.005 Kg/s
for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as
arrange above equation for diameter
\frac{\rho Q D}{\mu A }<2300
dynamic density of carbon dioxide = 1.47× Pa sec
density of carbon dioxide is 1.83 kg/m³
D = 0.344 m