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2 years ago

A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)

Engineering

1 answer:

LenaWriter [7]2 years ago

8 0

9514 1404 393

Answer:

see below

Explanation:

We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.

Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.

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Explanation:

Given Data:

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First has a natural water content of 25% = $\frac{25}{100}$ = 0.25

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$\frac{V_{2}}{V_{1}}=\frac{1+e_{2}}{1+e_{1}}$ ------> eq 1

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$e_{2}=w_{2} \times G_{s}$

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