Answer:
Explanation:
Length if the bar is 1m=100cm
The tip of the bar serves as fulcrum
A force of 20N (upward) is applied at the tip of the other end. Then, the force is 100cm from the fulcrum
The crate lid is 2cm from the fulcrum, let the force (downward) acting on the crate be F.
Using moment
Sum of the moments of all forces about any point in the plane must be zero.
Let take moment about the fulcrum
100×20-F×2=0
2000-2F=0
2F=2000
Then, F=1000N
The force acting in the crate lid is 1000N
Option D is correct
Answer:
Explanation:
Since the centripetal force F_C is, in this case, the gravitational force F_G exerted by the planet, we can say that:
In the case of the satellite A we have:
And in the case of the satellite B:
Finally, using these two expressions, we obtain :
In words, the centripetal acceleration a_b is equal to one fourth of a_0.
Answer:
The mass of the beam is 0.074 kg
Explanation:
Given;
length of the uniform bar, = 1m = 100 cm
Set up this system with the given mass and support;
0-----------------33cm-----------------------------------100cm
↓ Δ ↓
0.15kg m
Where;
m is mass of the uniform bar
Apply the principle of moment to determine the value of "m"
sum of anticlockwise moment = sum of clockwise moment
0.15kg(33 - 0) = m(100 - 33)
0.15(33) = m(67)
Therefore, the mass of the beam is 0.074 kg
Protons and Neutrons account for most of an atoms mass
Answer:
velocity = 15m/s
Explanation:
momentum of the object = 480kg/ms
nass of object = 32 kg
velocity of object = ?
momentum = velocity × mass
velocity = momentum / velocity
= 480kg/ms/32kg
= 15m/s