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Sloan [31]
3 years ago
5

Which quantity can be calculated using the equation E = mc2?

Physics
2 answers:
Mariulka [41]3 years ago
6 0

Explanation :

Einstein's equation is given by :

E=m\times c^2..............(1)

m is the mass

c is the speed of light c=3\times 10^8\ m/s

The energy needed to split an atom into separate protons, neutrons, and electrons can be calculated by using equation (1).

The energy needed to split the nucleus into separate protons and neutrons is called nuclear binding energy.

The energy needed to remove an electron from an atom is called ionization energy.

The energy needed to add an electron to an atom is called electron affinity.

So, the correct option is (A).

Goryan [66]3 years ago
3 0

Answer;

-The energy needed to split an atom into separate protons, neutrons, and electrons

Explanation;

E = mc² The equation is derived directly from Einstein’s Special Theory of Relativity .

Each of the letters of E = mc2 stands for a particular physical quantity. Writing them out in full we get:

Energy = mass × the speed of light squared

In other words:  E = energy (measured in joules, J),  m = mass (measured in kilograms, kg),  c = the speed of light (measured in metres per second, ms-1), but this needs to be squared.

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Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates
Alina [70]

Answer:

The capacitance of the deflecting plates is C=1.59 pF.

Explanation:

The expression for the capacitance of the capacitor in terms of area and distance is as follows;

C=\frac{\varepsilon _{0}A}{d}

Here, C is the capacitance, A is the area, d is the distance and \varepsilon _{0} is the absolute permittivity.

Convert the side of the square from cm to m.

s= 3.0 cm

s= 0.030 m

Calculate the area of the square.

A= s_^{2}

Put s= 0.030 m.

A=(0.030)_^{2}

A=9\times10^{-4}m^{-2}

Convert distance from mm to m.

d= 5.0 mm

d=5\times10^{-3}m

Calculate the capacitance of the deflecting plates.

C=\frac{\varepsilon _{0}A}{d}

Put d=5\times10^{-3}m, A=9\times10^{-4}m^{-2} and \varepsilon _{0}=8.85\times 10^{-12}Fm^{-1}.

C=\frac{(8.85\times 10^{-12})(9\times10^{-4})}{5\times10^{-3}}

C=1.59\times 10^{-12}F

C=1.59 pF

Therefore, the capacitance of the deflecting plates is C=1.59 pF.

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