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ryzh [129]
3 years ago
12

What do an earthquake wave and a light wave have in common?

Physics
2 answers:
rusak2 [61]3 years ago
5 0
It’s c.) I think so at least
Eddi Din [679]3 years ago
4 0

Answer:

I believe it's C im guessing im wrong if it's not C its got to be B

Explanation:

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How is it possible that only 92 elements are found in the natural world but there are millions of different types of molecules?
Katena32 [7]

Answer:

92 elemns in mendeleef oisv

bitly coin download

Explanation:

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3 years ago
Describe 3 uses of radioactive isotopes
pantera1 [17]
Cancer treatments, Radiography, food irradiation
8 0
2 years ago
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In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a s
zepelin [54]

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

3 0
3 years ago
A solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ω. The sphere is sl
pashok25 [27]

Explanation:

It is given that, a solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ω.The sphere is slowly heated until it reaches its melting temperature, at which point it flattens into a uniform disk of thickness D/2.

The angular momentum remains conserved in this case. The relation between the angular momentum and the angular velocity is given by :

I_s\times \omega_s=I_d\times \omega_d

Where

I_s\ and\ I_d are moment of inertia of sphere and the disk respectively

Here, volume before = volume after

\dfrac{4}{3}\pi (D/2)^3=\pi r^2\times D/2

r=\dfrac{D}{\sqrt{3} }=0.577\ D

Initial angular momentum,

L_i=I_s\times \omega_s

L_i=\dfrac{2mr^2}{5}\times \omega_s

L_i=\dfrac{2m(D/2)^2}{5}\times \omega_s

L_i=\dfrac{2mD^2}{20}\times \omega_s..........(1)

Final angular momentum,

L_d=I_f\times \omega_d

L_d=\dfrac{2mr^2}{5}\times \omega_d

L_d=\dfrac{2m(0.577D)^2}{5}\times \omega_d............(2)

From equation (1) and (2) :

\dfrac{2mD^2}{20}\times \omega_s=\dfrac{2m(0.577D)^2}{5}\times \omega_d

\dfrac{\omega_d}{\omega_s}=0.75

Hence, this is the required solution.

4 0
3 years ago
6. What is the definition of the word PER?
Montano1993 [528]

Answer:for each (used with units to express a rate). or divided by a line in the direction of.

Explanation:

3 0
4 years ago
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