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Anna71 [15]
3 years ago
6

Am I correct? Let me know and give an explanation.

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0
Yes you are correct
kenny6666 [7]3 years ago
6 0

Answer:

you are correct

Step-by-step explanation:

5x12=60-13+47

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In their last game the New England patriots scored 9 points in the first half in the second half they scored three less than two
Marat540 [252]

Answer:

3:5

Step-by-step explanation:

first half : 9

second half : 15

9:15 = 3:5

5 0
3 years ago
Read 2 more answers
(AP Calc) the graph of the function f shown above has three line segments....
I am Lyosha [343]

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 1, 6 ] and from the graph

f(b) = f(6) = 0

f(a) = f(- 1) = 0, thus

average rate of change = \frac{0-0}{6+1} = \frac{0}{7} = 0

7 0
3 years ago
What is exponential rate of change
hammer [34]

Answer:

Exponential growth refers to an increase based on a constant multiplicative rate of change over equal increments of time,that is a percent increase of the original amount over time.

8 0
3 years ago
Which expression is equivalent to 4+2(1+3x)?
Likurg_2 [28]

Answer:

6+18x

Step-by-step explanation:

=6(1+3x)

=6×1+6×3x

=6+18x

7 0
3 years ago
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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