Answer:
Angle of projection from the horizontal will be 
Explanation:
We have given that range of the projectile is 10 times the height of the projectile
Let the projectile is projected with velocity u at an angle 
Range of the projectile is equal to 
And height of the projectile is equal to 
Now according to question range is 10 times of height
So 




So angle of projection from the horizontal will be 
Answer:
a) -35.6°C
b) 237.4 K
Explanation:
To convert temperature from degree celsius to degree fahrenheit, use the formula below:

a) Therefore to convert -32°F to celsius, substitute it into the celsius

b) To covert to the Kelvin scale, use the formula below
Answer:
Distance = 25000000 miles
Time = 50 hours
Explanation:
Venus is the closest planet to Earth. It is about 25 million miles away from Earth. Its precise distance depends on where both Venus and Earth are in their respective orbits
Given that
Speed V = 500000 mph
Distance d = 25 000,000 miles
Speed = distance/ time
Time = distance/speed
Time = 25000000/500000
Time = 50 hours
It will therefore take 50 hours to get to venus at that speed.