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Lyrx [107]
3 years ago
12

What will happen to an object's wavelength as the object moves towards you?

Physics
2 answers:
UkoKoshka [18]3 years ago
6 0

Answer: The correct answer is "the wavelength will get shorter".

Explanation:

Red shift: In red shift, Light changes as the object in space (such as galaxies or stars) moves away from us then the light is shifted to red end. In this case, the light is shifted to longer wavelength.

Blue shift: In blue shift, Light changes as the object in space (such as galaxies or stars) moves towards from us then the light is shifted to blue end. In this case, the light is shifted to shorter wavelength.

In the given problem, the object moves towards us, then the wavelength of the object gets shorter.

Ilia_Sergeevich [38]3 years ago
5 0
The wavelength will get shorter
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A balloon has a volume of 3.0 l at 25°c. what is the approximate volume of the balloon at 50°c?
mart [117]
Sorry i dont know this one
6 0
3 years ago
Under which condition will air behave as conductor? a) low altitude b) high humidity c) low humidity d) high pressure
Solnce55 [7]

Air is a better conductor when the humidity is high. 

That's why you cannot zap your sister on a humid or rainy day,
even after scuffing your feet on the carpet.  The charge that you
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4 0
3 years ago
Planet-X has a mass of 3.42×1024 kg and a radius of 8450 km. What is the First Cosmic Speed i.e. the speed of a satellite on a l
tino4ka555 [31]

Answer:

First cosmic speed = 5195.74m/s

Second cosmic speed = 7346.05m/s

The raduis of the synchronous 0rbit of satellite is 2.80×10^7m

Explanation:

The first cosmic speed Is determined using the Orbital speed equation which is given by:

V = Sqrt(GM/r)

Where G = gravitational constant = 6.67 ×10^-11

M = Mass of planet

r = radius of the planet

V = Sqrt (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt (2.28×10^14)/(8450×10^3)

V = Sqrt ( 26995739.64)

V = 5195.75m/s

The second cosmic speed is given by :

V = Sqrt(2 × GM)/r

V = Sqrt (2 × (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt( 4.5×10^14)/ (8450×10^3)

V = Sqrt(53964497.04)

V = 7346.05m/s

The raduis of the synchronous orbit if the satellite around the planet is given by:

r = Cuberoot(T^2GM/4 pi r^2where T is the period of rotation of the planet in second

Given :

T = 17.1 hours converting to seconds

T = 17.1 ×60 ×60 = 61560 seconds

Substituting into the equation

r = Cuberoot ([(61560)^2×(6.67×10^-11)(3.42×10^24)/ (4 ×3.142×r^2)]

r = 2.80×10^7m

5 0
3 years ago
Read 2 more answers
When 2 moles of helium gas expand at a constant pressure p= 1.0×10^5 pascals, the temperature increase from 2 °c to 112 °c. If t
mote1985 [20]

Answer:

1,900 J

Explanation:

The number of moles of helium gas, n = 2 moles

The pressure of the helium gas, p = 1.0 × 10⁵ Pa

The initial temperature of the gas, T₁ = 2°C = 275.15 K

The final temperature of the gas, T₂ = 112°C = 385.15 K

The initial volume of the gas, V₁ = 45 liters

Cp = 20.8 J/(mol·K), Cv = 12.6 J/(mol·K)

The work done by the gas having constant pressure expansion is given as follows;

From the ideal gas law, we have;

V_2 = \dfrac{T_2 \times n \times R}{P}

Where;

R = The universal gas constant = 8.314 J/(mol×K)

Therefore, we get;

V_2 = \dfrac{385.15 \, K \times 2 \, moles \times 8.314 \, \dfrac{J}{mol \cdot K} }{1.0 \times 10^5 \ Pa} \approx 64.0 \, L

The work done, W = P ×ΔV = P × (V₂ - V₁)

∴ W = 1.0 × 10⁵ Pa × (64.0 L - 45.0 L) = 1,900 J

The work done by the gas as it expands, W = 1,900 J.

4 0
3 years ago
When you apply the ipde process, you may decide to?
vovangra [49]
When you apply the IPDE Process, you may decide to change speed, change direction, or communicate with others. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
8 0
3 years ago
Read 2 more answers
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