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klemol [59]
3 years ago
13

What is the mass of 1 l of water? what is its weight in newtons?

Physics
1 answer:
Ahat [919]3 years ago
8 0
9.8 N. is the your answer
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A cube with sides of area 22 cm2 contains a 21.2 nanoCoulomb charge. Find the flux of the electric field through the surface of
VladimirAG [237]

Answer:

Explanation:

According to Gausses theorem, electric flux coming out of  charge   on all sides q is equal to

q / ε₀

q is charge , ε₀  is permittivity of air whose value is given by

8.85 x 10⁻¹²; q = 21.2 x 10⁻⁹ C

Putting the values we get

FLUX = \frac{21.2\times10^{-9}}{8.85\times10^{-12}}

2.4 x 10³ Nm²/C

3 0
3 years ago
What parts are found in an electric generator
Len [333]

Here are a list of items I found.

some brushes

a armature

a permanent magnet

some slip rings

3 0
3 years ago
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the acceleration of a rocket traveling upward is given by a=(6+.02s)m/s^s, where s is in meters. Determine the rocket's velocity
NikAS [45]

Answer:

a) velocity v = 322.5m/s

b) time t = 19.27s

Explanation:

Note that;

ads = vdv

where

a is acceleration

s is distance

v is velocity

Given;

a = 6 + 0.02s

so,

\int\limits^s_0 {a} \, ds  = \int\limits^v_0 {v} \, dv\\ \int\limits^s_0 {6+0.02s} \, ds  = \int\limits^v_0 {v} \, dv\\ 6s + \frac{0.02s^{2} }{2} = \frac{1}{2} v^{2} \\v = \sqrt{12s + 0.02s^{2} } .....................1 \\\\\\

Remember that

v = \frac{ds}{dt} \\\frac{ds}{v} = dt\\\int\limits^s_0 {\frac{ds}{\sqrt{12s+0.02s^{2} } } } \, ds = \int\limits^t_0 {} \, dt \\t=  (5\sqrt{2} ) ln  \frac{| [s + 300 + \sqrt{(s^{2}  + 600s)} ] |}{300} .......2

substituting s = 2km =2000m, into equation 1

v = 322.5m/s

substituting s = 2000m into equation 2

t = 19.27s

8 0
3 years ago
How does Newton's second law apply to an "Egg Drop" experiment?
Black_prince [1.1K]
Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop
6 0
3 years ago
Calculate how much work is required to launch a spacecraft of mass mm from the surface of the earth (mass mEmE, radius RERE) and
SIZIF [17.4K]

Answer:

Work done = (1/2)[(Gmm_e)/(R_e)]

Explanation:

I've attached the explanations below.

5 0
3 years ago
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