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klemol [59]
3 years ago
13

What is the mass of 1 l of water? what is its weight in newtons?

Physics
1 answer:
Ahat [919]3 years ago
8 0
9.8 N. is the your answer
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Which of the following animals have adapted to live in the arctic tundra? (Select all that apply.)
sashaice [31]

Answer:

no way I had that question too :-O anyways here's the answer

Explanation:

willow ptarmigan and Walia ibex

5 0
3 years ago
A solid block is attached to a spring scale. When the block is suspended in air, the scale reads 21.2 N; when it is completely i
blsea [12.9K]

Answer:

7066kg/m³

Explanation:

The forces in these cases (air and water) are: Fa =mg =ρbVg Fw =(ρb −ρw)Vg where ρw = 1000 kg/m3 is density of water and ρb is density of the block and V is its density. We can find it from this two equations:

Fa /Fw = ρb / (ρb −ρw) ρb = ρw (Fa /Fa −Fw) =1000·(1* 21.2 /21.2 − 18.2)

= 7066kg/m³

Explanation:

8 0
3 years ago
Read 2 more answers
Pls i need help....
Natasha_Volkova [10]

Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Heat from the sun, or solar energy, powers the evaporation process.

And due to the water being hot, it added to the evaporation

MARK MEH BRAINLIEST

Explanation:

3 0
3 years ago
Can someone help me :)
Mamont248 [21]

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s

5 0
3 years ago
what is the energy required to melt down a 12,400g Gold bar assuming its temperature goes from 23c to 1,064c
sergejj [24]

1665183.6J

Explanation:

Given parameters:

Mass of Gold = 12400g

Initial temperature = 23°C

Final temperature = 1064°C

Unknown:

Energy required to melt = ?

Solution:

The amount of heat required to cause this temperature change to heat the gold bar is given as;

   H    =   m  c Ф

 m is the mass of gold bar

  c is the specific heat capacity of gold

  Ф is the heat change

 Specific heat capacity of gold = 0.129J/g°C

  H = m c (Ф₂ - Ф₁)

 H = 12400 x 0.129 x (1064 - 23) = 1665183.6J

learn more:

Specific heat capacity brainly.com/question/7210400

#learnwithBrainly

5 0
3 years ago
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