Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s
<span>x component = sine ( 32 ° ) * 20.583 = 10.91 m/s
hope this helps :)
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Answer:
Net displacement = 0
Distance traveled = 2PQ <_up and down
Explanation:
m= 60g = 60/1000 Kg = 0.06 Kg
v = 2cm3 = 2 * (0.01^3) m3 = 2 *10^-6 m3
Density= m/v = 6 * 10^-2 / 2 *10^-6 = 3 *10^4 Kg/m3
Answer:
a) In order to catch the ball at the level at which it is thrown in the direction of motion.
b)Speed of the receiver will be 7.52m/s
Explanation:
Calculating range,R= Vo^2Sin2theta/g
R= (20^2×Sin(2×30)/9.8 = 35.35m
Let receiver be(R-20) = 35.35-20= 15.35m
The horizontal component of the ball is:
Vox= Vocostheta= 20× cos30°
Vox= 17.32m/s
Time taken to coverR=35.35m with 17.32m/s will be:
t=R/Vox= 35.35/17.32
t= 2.04seconds
b)Speed required to cover 15.35m at 2.04seconds
Vxreciever= d/t = 15.35/2.04 = 7.52m/s
Net force acting on the car is 3 x 10^3 Newtons:
