3 years ago

Help me please <3...

Mathematics

2 answers:

Andru [333]3 years ago

8 0

3
7
-5
-7
-12
-19
-8
5
0
0
-6
second row
-13
-30
-5
-46
15
-8
-15
0
-7
-56
-36

kramer3 years ago

8 0

Answer:

(1) = 3

(2) = 7

(3) = -5

(4) = -7

(5) = -12

(6) = -19

(7) = -8

(8) = 5

(9) = 0

(10) = 0

(11) = -6

Second row:

(18) = -13

(19) = -30

(20) = -5

(21) = -46

(22) = 15

(23) = -8

(24) = -15

(25) = 0

(26) = -7

(27) = -56

(28) = -36

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Read 2 more answers

Given tan of theta = -2 and pi/2; find cos(2theta)

Nata [24]

Given tan of theta = -2 and pi/2; find cos(2theta)
The identity of cos (2 theta)= $cos(2\theta )=\frac{1-tan^2\theta }{1+tan^2\theta }$
Given tan of theta = -2 and pi/2.
So, let's plug in tan theta= -2
$cos(2\theta)= \frac{1-(-2)^2}{1+(-2)^2}$
= $\frac{1-4}{1+4}$ (Squaring)
= $\frac{-3}{5}$ (simplifying)
So, cos ( 2 theta) = -3/5.
Now we can plug in tan theta = π/2
$cos(2\theta)= \frac{1-(π/2)^2}{1+(π/2)^2}$
= $\frac{1-pi^2/4}{1+pi^2/4}$ (Squaring)
= $\frac{4-pi^2}{4+pi^2}$ Simplifying
So, cos ( 2 theta)= -3/5 and (4-pi^2)/(4+pi^2)