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3 years ago

When a wavelength (increases/decreases) the frequency (increases/decreases) and the energy (increases/decreases)

Chemistry

1 answer:

tangare [24]3 years ago

7 0

Answer:

As a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer. There are two basic types of waves: mechanical and electromagnetic

Explanation:

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0005x0.002 into scientific notation

geniusboy [140]

0005 * 0.002 = 5 * 0.002 = 0.010 = 10^-2

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3 years ago

Chemical name for organic compound CH2= CHCH2 CH2 CH2 CH3

kolbaska11 [484]

Answer:

The IUPAC name of the given compound is Pent-1-ene.

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Explanation:

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4 years ago

Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o

nadya68 [22]

Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

Number of moles of O2 = 9

The balanced chemical equation for the reaction is

2S (s)+3 O2 (g)→2SO3(g)

From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with $\frac{2 mol S x 9 mol O2}{3 mol O2}$

= 6 mol of S

Unreacted S = 7 - = 1 mol.

If a reaction vessel initially contains 7 mol S and 9 mol O2

1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible

6 0

4 years ago

What is science?

nikdorinn [45]

A body of knowledge and a process of gaining that knowledge

4 0

3 years ago

Nuclear decay occurs according to first-order kinetics. What is the half-life of europium-152 if a sample decays from 10.0 g to

djyliett [7]

Answer:

13.5 years

Explanation:

Initial Concentration [Ao] = 10g

Final Concentration [A] = 0.768g

Time t= 50 years

Half life t1/2 = ?

These quantities are related by the following equations;

ln[A] = ln[Ao] - kt ......(i)

t1/2 = ln(2) / k ...........(ii)

where k = rate constant

Inserting the values in eqn (i) and solving for k, we have;

ln(0.768) = ln(10) - k (50)

-0.2640 = 2.3026 - 50k

50k = 2.3026 + 0.2640

k = 2.5666 / 50 = 0.051332

Insert the value of k in eqn (ii);

t1/2 = ln(2) / k

t1/2 = 0.693 / 0.051332 = 13.5 years

4 0

3 years ago