Answer:
Molar mass = 103.0 g/mol,
0.728 mol NaBr
Explanation:
Molar mass M(NaBr) = M(Na) + M(Br) = 23.0 + 80.0 = 103.0 g/mol
75.0 g NaBr * 1 mol NaBr/103.0 g NaBr=0.728 mol NaBr
The question is incomplete, the complete question is;
1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?
A. CL2
B. SF6
C. Kr
D. UF6
E. Xe
Answer:
SF6
Explanation:
From Graham's law;
Let the rate of diffusion of oxygen be R1
Let the rate of diffusion of unknown base be R2
Let the molar mass of oxygen by M1
Let the molar mass of unknown gas be M2
Hence;
R1/R2 = √M2/M1
So;
2.14/1 = √M2/32
(2.14/1)^2 = M/32
M= (2.14/1)^2 × 32
M= 146.6
This is the molar mass of SF6 hence the answer above.
The mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
<h3>Calculating mass of a compound </h3>
From the question, we are to determine the mass of the given beryllium sulfide.
From the given information,
Number of moles of beryllium sulfide (BeS) given = 2.42 moles
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of BeS = 41 g/mol
Then,
Mass of BeS = 2.42 × 41
Mass of BeS = 99.22
Mass of BeS ≅ 99.2 g
Hence, the mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
Learn more on Calculating mass of a compound here: brainly.com/question/18142599
Words that includes names, places, geometric shapes and finally units of measure.
Answer:
The answer is 4778.4 cm (cubed)
Explanation:
V = (πr(squared)) x (h/3)
V = (π x 13(squared)) x (27/3)
V = 530.9291585 x 9
V = 4778.4
