The problem statement gives a relation between the amount removed from one bag and the amount removed from the other. It asks for the amount remaining in each bag. Thus, there are several choices for variables in this problem, some choices resulting in more complicated equations than others.
Let's do it this way: let x represent the amount remaining in bag 1. Then the amount removed from bag 1 is (100-x). The amount remaining in bag 2 is 2x, so the amount removed from that bag is (100-2x). The problem statement tells us the relationship between amounts removed:
... (100 -x) = 3(100 -2x)
... 100 -x -3(100 -2x) = 0 . . . . . . subtract the right side
... 5x -200 = 0 . . . . . . . . . . . . . . eliminate parentheses and collect terms
... x -40 = 0 . . . . . . . . . . . . . . . . .divide by 5
... x = 40 . . . . . . . . . . . . . . . . . . . add 40
- 40 kg is left in the first bag
- 80 kg is left in the second bag
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<u>Check</u>
The amount removed from the first bag is 60 kg. The amount removed from the second is 20 kg. The amount removed from the first bag is 3 times the amount removed from the second bag, as described.
Answer:
20 games were won and 12 games were lost.
Step-by-step explanation:
Bearing in mind that the major axis runs over the y-axis, therefore the "a" component will be under the fraction with the "y", check the picture below.
Answer:
Top box: Endpoint
Bottom box: Ray
Step-by-step explanation:
Assuming that the top box is supposed to be for the point shared by both rays, then it is a endpoint of the rays, as the lines do not continue past the point on the opposite side.
The bottom box will then be a ray, as no point is shown, and a arrow is used at the "end" of the line to signify that it will continue on <em>forever</em>.
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