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Alekssandra [29.7K]
3 years ago
7

Explain how Bohr's model built on the ideas of Einstein and Planck.

Chemistry
1 answer:
AlekseyPX3 years ago
7 0

Explanation:

Bohr built on Nicholson's idea by adopting the requirement that the angular momentum can have only certain discrete values related to Planck's constant. However Bohr's atom has many orbits for the electrons.

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Calculate the percentage composition of each element in calcium hydroxide
sp2606 [1]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

2 moles of O therefore 32g are O

2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

  • (40.08 / 74.08) . 100 = 54.1 %
  • (32 / 74.08) . 100 = 43.2 %
  • (2 / 74.08) . 100 = 2.7%
6 0
3 years ago
Determine if each statement below is True or False regarding Arrhenius and Br∅nsted-Lowry definitions for acids and bases.
Vlad1618 [11]

Answer:

All statements are true

Explanation:

Arrhenius theory:-

The Arrhenius theory was introduced introduced by Swedish scientist named Svante Arrhenius in 1887.

According to the theory, acids are the substances which dissociate in the aqueous medium to produce electrically charged atoms ( may be molecule). Out of these species furnished, one must be a proton or the hydrogen ion, H^+.

Hence, statement 1 is correct.

Bronsted-Lowry base is the specie which accepts the proton form the medium. For example, Benzoate ion is the conjugate base of the benzoic acid. It is a Bronsted-Lowry base and the dissociation of benzoate ion can be shown as:-

C_6H_5COO^-_{(aq)} + H_2O_{(l)}\rightleftharpoons C_6H_5COOH_{(aq)} + OH^-_{(aq)}

Hence, statement 2 is correct.

Acetic acid will dissociate as:-

CH_3COOH\rightleftharpoons CH_3COO^-+H^+

Hence, statement 3 is also correct.

5 0
3 years ago
Can anybody please with this ohms law
mixer [17]

Answer:

feyyeyeuueuehehheueueieuhegebrbjrirororkoeorororproororororri9r

Explanation:

eejjeididodjdjrirr

7 0
3 years ago
Calculate the enthalpy change (in joules) involved in converting 5.00 grams of water at 14.0 °c to steam at 115 °c under a const
tensa zangetsu [6.8K]

Enthalpy change is the term given to the concentration of the heat absorbed or evolved in a reaction carried out at a constant pressure. It is given by the symbol ΔH.

Enthalpy change = m (Cwater × dT + Hvap + Csteam × dT

dHvap = 40.67 kJ/mol = 40.67 × 103/18 = 2259.4 J/g

Enthalpy change = 5.00 [4.18 × (100-14) + 2259.4 + 1.84 × (115-100)]

= 13232.4 J

7 0
3 years ago
What's a wind up toy useful energy output
exis [7]
Potential energy stored in a spring => kinetic energy of a toy
6 0
3 years ago
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