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defon
3 years ago
14

How many protons does the bohr model have for helium?

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
8 0

Answer:

2 protons per atom of Helium

Explanation:

The number of proton in a given element is given by its place on the periodic table which is for He 2 protons b/c the atomic number for He is 2.

Other Examples:

Hydrogen (H-1) or Protium has 1 proton b/c its atomic number is 1.

Magnesium (Mg-24) has 24 protons  b/c  its atomic number is 24.

Lead (Pb-207) has 82 protons b/c its atomic number is 82.

Uranium (U-238) has 92 protons b/c its atomic number is 92.

The periodic table order of arrangement of elements is based upon 'The Periodic Law'. => The chemical and physical properties of the elements is a periodic function of atomic numbers, or number of protons in the nucleus.

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A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the di
irinina [24]

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

<u>Answer:</u> The percent of dissociation of trimethylacetic acid is 19.5 %

<u>Explanation:</u>

We are given:

Concentration of trimethylacetic acid = 0.21 mM  = 0.00021 M    (Conversion factor:  1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

                     C_4H_9COOH\rightleftharpoons C_4H_9COO^-+H^+

<u>Initial:</u>                   0.00021

<u>At eqllm:</u>             0.00021-x              x            x

The expression of K_a for above equation follows:

K_a=\frac{[C_4H_9COO^-][H^+]}{[C_4H_9COOH]}

We know that:

K_a\text{ for }C_4H_9COOH=1\times 10^{-5}

Putting values in above expression, we get:

1\times 10^{-5}=\frac{x\times x}{(0.00021-x))}\\\\x=0.000041,-0.000051

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the fraction of dissociation, we use the equation:

\text{Percent of dissociation}=\frac{[H^+]}{[C_4H_9COOH]}\times 100

Putting values in above equation, we get:

\text{Percent of dissociation}=\frac{0.000041}{0.00021}\times 100\\\\\text{Percent of dissociation of trimethylacetic acid}=19.5%

Hence, the percent of dissociation of trimethylacetic acid is 19.5 %

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