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irga5000 [103]
3 years ago
8

Don Walsh and Jacques Piccard:

Physics
2 answers:
dezoksy [38]3 years ago
8 0
The answer would be....

Explored the deepest known ocean trench.
eimsori [14]3 years ago
5 0

Answer:Explore the deepest known ocean trench and designed submarine for underwater research.

Explanation:Jacques sought financial help from the U.S. Navy, which at that time was exploring various ways of designing submarines for underwater research. ... On 23 January 1960, Piccard and Lt. Don Walsh reached the floor of the Mariana Trench located in the western North Pacific Ocean.

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A pair of slits in a double slit experiment are illuminated with monochromatic light of wavelength 480 nm. The slits are separat
Romashka-Z-Leto [24]

Using the appropriate approximations:

dx/L = mλ

d = slit separation

x = fringe spacing

L = distance between slits and screen

m = some integer, used to determine the distance from the central bright fringe to another bright fringe


We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1


Given values:

d = 1.0mm

L = 2.0m

λ = 480nm


Substitute the terms in the equation with our given values and solve for x:

1.0*10⁻³*x/2 = 480*10⁻9

<h3>x = 0.96mm</h3>
8 0
3 years ago
Studying neutrinos helped to explain how our Sun works but led to changes in theories of particle physics, how is this process c
julsineya [31]

Explanation:

Yes,  evidently, the process is consistent with the scientific process because in scientific process falsification and modification are two very important traits. So this new concept have modified the existing theories.

Through the modification a theory is adjusted without undermining other discovering made through the theory's prediction.

There are many other evidences that prove this fact for example Einstien's Theory of relativity also changes the existing concepts.

3 0
3 years ago
A world-class sprinter running a 100 m dash was clocked at 5.4 m/s 1.0 s after starting running and at 9.8 m/s 1.5 s later. In w
cupoosta [38]

Answer:

<em>The output power is greater in the interval from 1.0 s to 2.5 s</em>

Explanation:

<u>Physical Power </u>

It measures the amount of work W an object does in certain time t. The formula needed to compute power is

\displaystyle P=\frac{W}{t}

Work can be computed in several ways since we are given the motion conditions, we'll use this formula, for F= applied force, x=distance parallel to F

W=F.x

The second Newton's law gives us the net force as

F=m.a

being m the mass of the object and a the acceleration it has for a given period of time. In our problem, we have two different behaviors for each interval and we must calculate this force since the acceleration is changing. Let's calculate the acceleration in the first interval. We can use the formula for the final speed vf knowing the initial speed vo (which is 0 because the sprinter starts from rest), the acceleration a, and the time t:

v_f=v_o+at

v_f=at

Solving for a

\displaystyle a=\frac{v_f}{t}={5.4}{1}

a=5.4\ m/s^2

The distance traveled in the interval is given by

\displaystyle x=v_o.t+\frac{a.t^2}{2}

Since vo=0

\displaystyle x=\frac{a.t^2}{2}=\frac{5.4(1)^2}{2}

x=2.7\ m

The force is given by

F=m.a

We don't know the value of m, so the force is

F=2.7m

Computing the work done by the sprinter

W=F.x=2.7m(5.4)

W=14.58m

The power is finally computed

\displaystyle P=\frac{W}{t}=\frac{14.58m}{1}

P=14.58m

During the second interval, from t=1 sec to 1.5 sec, the speed changes from 5.4 m/s to 9.8 m/s. This allows us to compute the second acceleration

\displaystyle a=\frac{v_f-v_o}{t}=\frac{9.8-5.4}{0.5}

a=8.8\ m/s^2

The distance is

\displaystyle x=(5.4).(0.5)+\frac{8.8(0.5)^2}{2}

x=3.8\ m

The net force is

F=m(8.8)=8.8m

The work done by the sprinter is now computed as

W=8.8m(3.8)=33.44m

At last, the output power is

\displaystyle P=\frac{33.44m}{0.5}=66.88m

By comparing both results, and being m the same for both parts, we conclude the output power is greater in the interval from 1.0 s to 2.5 s

6 0
3 years ago
A scooter is accelerated from rest at the rate of 8m/s
algol13

Explanation:

time=Distance/speed

t=32/8

t=4 seconds

8 0
3 years ago
75 kg + 1352 g = ______________g?
JulsSmile [24]
Answer is 76,352 just look it up
8 0
3 years ago
Read 2 more answers
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