The equipotential lines are lines or surfaces that have the same power, therefore we can move in them without carrying out work between equipotential lines, work must be carried out, therefore the electric field changes.

The electric field and the potential are related by

E = - dV / dx

therefore when the change is faster, that is, the equipotential lines are closer, the greater the electric field must be.

4 0

4 years ago

Part A What width sit will produce a central maximum that is 2.50 em wide on a screen 2 20 m from the slit? Express your answer

Svet_ta [14]

Answer:

9.82×10⁻² m

Explanation:

w = Width of central maximum = 2.5 cm = 0.025 m

D = Distance between screen and slit = 2.2 m

λ = Wavelength of green light = 558 nm = 558×10⁻⁶ m

a = Width of slit

$w=\frac{2\lambda D}{a}\\\Rightarrow a= \frac{2\lambda D}{w}\\\Rightarrow a= \frac{2\times 558\times 10^{-6}\times 2.2}{0.025}\\\Rightarrow a= 98208\times 10^{-6}= 9.82\times 10^{-2}\ m$

∴ Width of slit is 9.82×10⁻² m

7 0

4 years ago