Is this a chemistry question ?
Answer:
Given, length of wire, l = 2m
cross sectional area , A = 10^-4 m²
Load , F = 102kgwt = 102 × 9.8 N
extension of wire, ∆l = 0.1cm = 0.001m
Longitudinal stress = F/A
= 102 × 9.8/(10^-4)
= 999.6 × 10^4 ≈ 1 × 10^7 N/m²
Longitudinal strain. = extension of wire/original length of wire = ∆l/l
= 10^-3/2 = 5 × 10^-4
we know, Young's modulus = longitudinal stress/longitudinal strain
= 1 × 10^7/5 × 10^-4
= 20 × 10^9 N/m²
Explanation:
:D
Answer:
Option (A)
Explanation:
Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).
Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB
Area of triangle AOB = 
= 
= 80 m
Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD
Area of ΔBCD =
= 80 m
Total displacement of the particle from t = 0 to t = 80 seconds,
= 80 + 80
= 160 m
Option (A) will be the answer.
Answer:
Thomson
Explanation:
Thomson in 1904 soon after the discovery of the electron, but before the discovery of the atomic nucleus, the model tried to explain two properties of atoms then known: that electrons are negatively-charged particles and that atoms have no net electric charge.
