Answer:
The answer to your question is: ΔH = 1637.8
Explanation:
Hess' law: This law states that the enthalpy change can be calculated even if it is not calculated directly.
"if a chemical change takes place by several routes, the overall enthalpy change is the same regardless the route".
Process
A) N2(g)+O2(g)—->2NO(g) Δ H= -180.5
B) N2(g) + 3H2(g) ——> 2NH3(g) Δ H= -91.8
C)2H2(g)+ O2(g) —-> 2H2O(g) Δ H= -486.6
The result must be:
4NH3(g)+5O2(g)—->4NO(g)+6H2O(g)
Turn letter B and multiply it by 2
4NH3 ⇒ 2N2 + 6H2 ΔH = 183.6
Multiply letter A by 2
2N2 + 2O2 ⇒ 4 NO ΔH = -361
Multiply letter C by 3
6H2 + 3O2 ⇒ 6H2O ΔH = -1459.8
Finally we add the equations up and simplify then:
4NH3 + 5O2 ⇒ 4NO + 6 H2O
And we add the ΔH = 183.6 - 361 - 1459.8
= -1637.8
...if you use magnetso this is a mixture
p/s: or this is physical process
sorry if I'm wrong
Answer:
C
In an exothermic reeaction, the energy of products is less than the energy of reactants.
Explanation:
Answer:
Cleaning agents, tissue disgestion
Explanation:
Answer:
pH = 11.60
Explanation:
When we add a base, we are increasing [OH⁻], so the pH will be totally basic.
pH of water = 7
Basic pH > 7
We are adding 2 M . 1 mL = 2 mmoles
2 mmoles of OH⁻ are contained in 501 mL of total volume.
[OH⁻] = 2 mmol / 501 mL = 3.99×10⁻³ M
- log 3.99×10⁻³ M = 2.39 → pOH
pH = 14 - pOH → 11.61
Water equilibrium
2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 1×10⁻¹⁴
NaOH → Na⁺ + OH⁻
