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MAVERICK [17]
3 years ago
7

In which scenarios would the amount of substance remaining be 200 mg? Select all that apply. 800 mg of a radioactive substance w

ith a half-life of 2 years after decaying for 4 years 1,000 mg of a radioactive substance with a half-life of 5 years after decaying for 20 years 300 mg of a radioactive substance with a half-life of 1 year after decaying for 1 year 600 mg of a radioactive substance with a half-life of 6 hours after decaying for 18 hours 400 mg of a radioactive substance with a half-life of 8 hours after decaying for 8 hours
Chemistry
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

e)  400 mg of a radioactive substance with a half-life of 8 hours after decaying for 8 hours

a) 800 mg of a radioactive substance with a half-life of 2 years after decaying for 4 years.

Explanation:

a) 800 mg of a radioactive substance with a half-life of 2 years after decaying for 4 years.

Number of half lives passed = Time elapsed/ half life

Number of half lives passed = 4 year/2 year

Number of half lives passed = 2

at time zero = 800 mg

At first half life = 800 mg/2 = 400 mg

At 2nd half life = 400 mg/2 = 200 mg

b) 1,000 mg of a radioactive substance with a half-life of 5 years after decaying for 20 years

Number of half lives passed = Time elapsed/ half life

Number of half lives passed = 20 year/ 5 year

Number of half lives passed = 4

at time zero = 1000 mg

At first half life = 1000 mg/2 = 500 mg

At 2nd half life = 500 mg/2 = 250 mg

At 3rd half life = 250 mg/2 =  125 mg

At 4th half life = 125 mg/2 = 62.5 mg

c) 300 mg of a radioactive substance with a half-life of 1 year after decaying for 1 year

Number of half lives passed = Time elapsed/ half life

Number of half lives passed = 1 year/ 1 year

Number of half lives passed = 1

at time zero = 300 mg

At first half life = 300 mg/2 = 150 mg

d) 600 mg of a radioactive substance with a half-life of 6 hours after decaying for 18 hours

Number of half lives passed = Time elapsed/ half life

Number of half lives passed = 18 hours / 6 hours

Number of half lives passed = 3

at time zero = 600 mg

At first half life = 600 mg/2 = 300mg

At 2nd half life = 300 mg/2 = 150 mg

At 3rd half life = 150 mg/2 =  75 mg

e)  400 mg of a radioactive substance with a half-life of 8 hours after decaying for 8 hours

Number of half lives passed = Time elapsed/ half life

Number of half lives passed = 8 hours / 8 hours

Number of half lives passed = 1

at time zero = 400 mg

At first half life = 400 mg/2 = 200 mg

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How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

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In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

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The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

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"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

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