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Yanka [14]
2 years ago
13

Calcium + Sodium Bromide balance

Chemistry
1 answer:
kompoz [17]2 years ago
4 0
2Nabr +Ca(oh)2——->CaBr2+2NaOH
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If nitrogen-13 has a half life of 2.5 years, how much remains from a 100g sample after 7.5 years
Sonbull [250]

Answer:

12.50g

Explanation:

T½ = 2.5years

No = 100g

N = ?

Time (T) = 7.5 years

To solve this question, we'll have to find the disintegration constant λ first

T½ = In2 / λ

T½ = 0.693 / λ

λ = 0.693 / 2.5

λ = 0.2772

In(N/No) = -λt

N = No* e^-λt

N = 100 * e^-(0.2772*7.5)

N = 100*e^-2.079

N = 100 * 0.125

N = 12.50g

The sample remaining after 7.5 years is 12.50g

5 0
3 years ago
An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes t
mihalych1998 [28]

Answer:

The answer is "11.07 g".

Explanation:

Isoamyl alcohol is a reagent restriction

Isoamyl alcohol Moles: 

= \frac{7.5}{88.15} \\\\ =0.085

Moles only with the shape of isoamyl acetate are equivalent to numbers.

Isoamyl acetate grams:

= 0.085 \times 130.19\\\\ = 11.07 \ g

3 0
3 years ago
QUESTION 11
Iteru [2.4K]
I actually don’t know but good question
6 0
3 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system
AleksAgata [21]
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w

Clearing the specific heat of the unknown substance:

c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}

c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
6 0
3 years ago
How many total phosphorus atoms are shown in the following: Al2P3? *
Wewaii [24]

Answer:

3 P atoms

Explanation:

Al₂P₃ => contains 2 Aluminum ions (2Al⁺³) and 3 Phosphide ions (3P⁻³) ... The ions (charged particles) are from atoms that have lost or gained electrons during the bonding process. So, Al₂P₃ => P⁻³ ions from 3 P atoms.

6 0
3 years ago
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