1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
3 years ago
6

It is common to mix polar solvents (e.g., acetone) with non-polar solvents (e.g., hexane) to obtain an eluting solvent of interm

ediate polarity. Would it be appropriate to use a water-DMSO mixture
Chemistry
1 answer:
hammer [34]3 years ago
6 0

Answer:

No, it is not appropriate to mix water and DMSO

Explanation:

We have to realize that DMSO is a highly polar solvent and water is a highly polar solvent. The question explicitly says that our target is to produce a solvent of<u><em> intermediate polarity</em></u>.

We can only do this by mixing a polar and a nonpolar solvent. We have been given the example of the mixture of acetone/hexane which is quite a perfect mixture.

Thus, it is inappropriate to mix DMSO and water.

You might be interested in
Hard water often contains dissolved Mg2+and Ca2+ions. Water softeners often use sodium carbonate to soften the water. Sodium car
Dvinal [7]

Answer:

32.5g of sodium carbonate

Explanation:

Reaction of sodium carbonate (Na₂CO₃) with Mg²⁺ and Ca²⁺ as follows:

Na₂CO₃(aq) + Ca²⁺(aq) → CaCO₃(s)

Na₂CO₃(aq) + Mg²⁺(aq) → MgCO₃(s)

<em>1 mole of carbonate reacts per mole of the cations.</em>

<em />

To know the mass of sodium carbonate we must know the moles of carbonate we need to add based on the moles of the cations:

<em>Moles Mg²⁺:</em>

2.91L * (0.0661 moles MgCl₂ / 1L) = 0.192 moles MgCl₂ = Moles Mg²⁺

<em>Moles Ca²⁺:</em>

2.91L * (0.0396mol Ca(NO₃)₂ / 1L) = 0.115 moles Ca(NO₃)₂ = Moles Ca²⁺

That means moles of sodium carbonate you must add are:

0.192 moles + 0.115 moles = 0.307 moles sodium carbonate.

In grams (Using molar mass Na₂CO₃ = 105.99g/mol):

0.307 moles Na₂CO₃ * (105.99g / mol) =

<h3>32.5g of sodium carbonate</h3>
3 0
3 years ago
A container with a volume of 893L contains how may moles of air at STP?
Vadim26 [7]

Answer:

i think 54

Explanation:

7 0
3 years ago
A chemist observes that a large molecule reacts as if it were much smaller. The chemist proposes that the molecule is folded in
nadezda [96]

Answer:

Hypothesis

Explanation:

The following steps are applicable when we wish to prove a specific fact:

  • a hypothesis is made; this is a statement that we provide after some observations and we wish to either prove or deny it;
  • multiple experiments are carried out in order to gather significantly substantial amount of data that can be then further analyzed and any tendencies can be noticed;
  • based on the data gathered, conclusions are made: we either prove or deny the hypothesis. If hypothesis is proved, it may become a theory over long time.

In the context of this problem, we're at the first step where we make a hypothesis.

6 0
3 years ago
A steel beam that is 7.00 m long weighs 326 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
GrogVix [38]

Answer:

The answer to the question is

Suki is 1.12 m close to the end of the steel beam before the beam begins to tip

Explanation:

To solve the question we list out the known variables first

Length of steel beam, L = 7.00 m

Weight  of steal beam W = 326 N

Distance between supports = 3.00 m

Weight of Suki = 555 N

By moments theory, the sum of moments about a point = 0

and assuming the steal beam is uniform, the weight of the beam will act at the center of the beam

As described the supports are 2.00 m from each end of the beam thus

taking moments about one of the support with Suki between  the end of the beam and the support we have

Distance from center of beam to support = 1.5 m

Distance of Suki to the nearest support = x m

therefore 555 × x + 326 × 1.5 = 0

or x = -0.881 m on the other side of the support

Therefore Suki is (2 - 0.881) m or 1.12 m close to the end before the beam begins to tip

7 0
3 years ago
What is the volume of a 5.30g piece of aluminum? The density for aluminum is 2.70mL
Makovka662 [10]

Answer:

1.96mL

Explanation:

Density = mass/volume, and rearranged to solve for volume, volume = mass/density.

So:

volume = 5.30g/2.70g/mL = 1.96mL (assuming your unit was g/mL for density)

7 0
3 years ago
Other questions:
  • If 25.0 ml of seawater has a mass of 25.895 g and contains 1.295 g of solute, what is the mass/mass percent concentration of sol
    12·1 answer
  • Given: 2LiBr + I2 → 2LiI + Br2 Calculate the mass of bromine produced when 9.033 × 1023 particles of iodine (I2) react completel
    8·1 answer
  • An element that has been broken down and released particles and energy is said to be ____.
    15·2 answers
  • How many moles of N are in 0.173 g of N2O?
    5·1 answer
  • When you add a controlled amount of substance known as an impurity to a pure semiconductor, its conductivity increases. This pro
    12·1 answer
  • Copper (II) sulfate solution reacts with magnesium metal ? what is the equation for this reaction?
    8·1 answer
  • What happens to the density of a box full of leaves if you crush up all the leaves and place them in another box
    11·1 answer
  • Two identical sister chromatids are held together at what
    12·1 answer
  • You and your science group have been handed five mineral samples to identify. First, you sort the minerals by color. One has man
    6·1 answer
  • Calculate the Molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!