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Nataly [62]
3 years ago
14

12x + 10 = px + 10

Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0
B because it juss makes sense
You might be interested in
Help needed! no links please, they're annoying.
denis23 [38]
The area of a rectangle is length*width.

The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.

Start by writing out this equation:
A=l*w

Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)

Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.

After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.

I hope this helped!
4 0
3 years ago
Plz help me plz it’s really important
Juli2301 [7.4K]

Answer:

The circle at point-2 is not filled which means-2 is not included whereas the circle at point 5 is filled which means 5 is included in the interval of the given line.

The interval notation for the above line

<h3>-2<x≤5</h3>

4 0
3 years ago
4x + 6 &lt; -6<br><br> Show steps used to solve the problem :)
Sergeeva-Olga [200]

Answer:

hope it helps you........

7 0
3 years ago
Read 2 more answers
Part B
stira [4]
<h3>Given:</h3>
  • Radius of 50 point region= 3 in
  • Width of other regions= 4 in
<h3>To find:</h3>

The area of the target which earns 30 points on a throw.

<h3>Solution:</h3>

\huge\boxed{Formula: a= \pi{r}^{2}}

4+3

=7

Let's solve

We have to find the answer in terms of π so, we'll just have to multiply the radius by itself.

a={7}^{2}

\large\boxed{a= 49 \pi\: {in}^{2}}

<u>Hence,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the target which earns 30 points on a throw</u><u> </u><u>is</u><u> </u><u>4</u><u>9</u><u>π</u><u> </u><u>square</u><u> </u><u>inches</u><u>.</u>

<u>Answer</u><u>=</u><u> </u><u>Option</u><u> </u><u>B</u>

7 0
2 years ago
I do not get this at all
Rina8888 [55]
I had problems with the same thing when i was in middle school gotta take it step by step
7 0
3 years ago
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