Answer:
17.2mL are needed
Explanation:
<em>The pH curve for titration of 50.0 mL of a 0.100 M solution of hydrochloric acid</em>
<em />
A strong acid as HCl reacts with a strong base as NaOH producing water and a salt. The chemical equation is:
HCl + NaOH → H₂O + NaCl
<em>Where 1 mole of HCl reacts per mole of NaOH</em>
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To solve this question we must find the moles of HCl added = Moles NaOH you must add to reach the equivalence point. With these moles and the molar concentration we can find the volume that would be needed as follows:
<em>Moles HCl:</em>
50.0mL = 0.0500L * (0.100moles / L) = 0.00500 moles HCl = Moles NaOH
<em>Volume NaOH:</em>
0.00500 moles NaOH * (1L / 0.290moles) = 0.0172L NaOH =
<h3>17.2mL are needed</h3>
1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?
Answer:
v = 0.94 mL
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Given data:
Density of soap = 1.06 g/mL.
Mass = 1 g
Volume = ?
Solution:
d = m/v
v = m/d
v = 1 g/1.06 g/mL
v = 0.94 mL
2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?
Answer:
m = 1370 g
Given data:
Density of soap = 1.37 g/mL.
Mass = ?
Volume = 1.0 L ( 1000 mL)
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
m = d × v
m = 1.37 g/mL × 1000 mL
m = 1370 g
3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?
Answer:
v = 29.2 mL
Given data:
Density of soap = 0.754 g/mL.
Mass = 22 g
Volume = ?
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
v = m/d
v = 22 g/0.754 g/mL
v = 29.2 mL
well, with proper tools you can check a substances buoyancy, and hardness.
Answer:
Hope the above picture might help you :)
