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Savatey [412]
4 years ago
15

How many moles are equal to 89.23 g of calcium oxide?

Chemistry
2 answers:
adelina 88 [10]4 years ago
0 0
The molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol 
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO
erica [24]4 years ago
0 0

Answer : 1.593 moles are equal to 89.23 g of calcium oxide.

Solution : Given,

Mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Formula used :

\text{Moles of }CaO=\frac{\text{Mass of }CaO}}{\text{Molar mass of }CaO}

Now put all the given values in this formula, we get the moles of calcium oxide.

\text{Moles of }CaO=\frac{89.23g}{56g/mole}=1.593moles

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

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What is the correct answer to the following expression: (72.61 - 68.59) x 18.76? Be sure to express your answer using the correc
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A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc
Elan Coil [88]

Answer:

a. Moles of NaOH  = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

a.

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For NaOH :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of NaOH :

Moles=0.1052 \times {15.62\times 10^{-3}}\ moles

Moles of NaOH  = 0.001643 moles

b.

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

c.

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains \frac{0.296}{1.159}\times 1.213 g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0
3 years ago
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