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4 years ago

How many moles are equal to 89.23 g of calcium oxide?

2 answers:

0 0

The molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO

erica [24]4 years ago

0 0

Answer : 1.593 moles are equal to 89.23 g of calcium oxide.

Solution : Given,

Mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Formula used :

$\text{Moles of }CaO=\frac{\text{Mass of }CaO}}{\text{Molar mass of }CaO}$

Now put all the given values in this formula, we get the moles of calcium oxide.

$\text{Moles of }CaO=\frac{89.23g}{56g/mole}=1.593moles$

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

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Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 L of carbon dioxide at 20.0 °C and

swat32

Answer:

$\%\ mass\ of\ CaCO_3=93.37\ \%$

Explanation:

Given that:

Pressure = 791 mmHg

Temperature = 20.0°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (20 + 273.15) K = 293.15 K

T = 293.15 K

Volume = 100 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 62.3637 L.mmHg/K.mol

Applying the equation as:

791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol × 293.15 K

⇒n of $CO_2$ produced = 0.0493 moles

According to the reaction:-

$CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2$

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts

0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts

Moles of calcium carbonate reacted = 0.0493 moles

Molar mass of $CaCO_3$ = 100.0869 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0493\ mol= \frac{Mass}{100.0869\ g/mol}$

$Mass_{CaCO_3}=4.93\ g$

Impure sample mass = 5.28 g

Percent mass is percentage by the mass of the compound present in the sample.

$\%\ mass\ of\ CaCO_3=\frac{Mass_{CaCO_3}}{Total\ mass}\times 100$

$\%\ mass\ of\ CaCO_3=\frac{4.93}{5.28}\times 100$

$\%\ mass\ of\ CaCO_3=93.37\ \%$

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3 years ago

Redox 1/2 reaction Cu(s) + 2 AgC2H3O2(aq) = Cu(C2H3O2)2(aq) + 2 Ag(s)

Anna11 [10]

Explanation:

Reaction:

Cu + 2AgC₂H₃O₂ → Cu(C₂H₃O₂)₂ + 2Ag

The problem is to split the reaction into oxidation and reduction halves:

The oxidation half is the sub-reaction that undergoes oxidation

The reduction half is the one that undergoes reduction:

The ionic equation:

Cu + 2Ag⁺ + 2C₂H₃O₂⁻ → Cu²⁺ + 2C₂H₃O₂⁻ + 2Ag

Oxidation half:

Cu → Cu²⁺ + 2e⁻

Reduction half:

2Ag⁺ + 2e⁻ → 2Ag

C₂H₃O₂⁻ is neither oxidized nor reduced in the reaction.

learn more:

Oxidation state brainly.com/question/10017129

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4 0

3 years ago

A 30.5-g sample of water at 300. K is mixed with 48.5 g water at 350. K. Calculate the final temperature of the mixture assuming

ahrayia [7]

Answer:

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Explanation:

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3 years ago

How come there is only 3 C5H12 isomers?

liraira [26]

That's because the first and last carbon atoms cannot be branched to form an isomer . Therefore only the three middle carbon atoms can form isomers.

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3 years ago

A Carnot cycle operates between the temperatures limits of 400 K and 1600 K, and produces 3600 kW of net power. The rate of entr

TiliK225 [7]

The rate of entropy change:

The rate of entropy change of the working fluid during the heat addition process is 3 kW/K

What is the Carnot cycle?

The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession.
The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.

The entropy of a system:

The rate of heat addition is expressed as,

Q = $\frac{WT_{H}}{T_{H}- T_{L}}$