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4 years ago

How many moles are equal to 89.23 g of calcium oxide?

2 answers:

0 0

The molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO

erica [24]4 years ago

0 0

Answer : 1.593 moles are equal to 89.23 g of calcium oxide.

Solution : Given,

Mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Formula used :

$\text{Moles of }CaO=\frac{\text{Mass of }CaO}}{\text{Molar mass of }CaO}$

Now put all the given values in this formula, we get the moles of calcium oxide.

$\text{Moles of }CaO=\frac{89.23g}{56g/mole}=1.593moles$

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

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6.02*10²³y = 0.270*10²³
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