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4 years ago

How many moles are equal to 89.23 g of calcium oxide?

2 answers:

0 0

The molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO

erica [24]4 years ago

0 0

Answer : 1.593 moles are equal to 89.23 g of calcium oxide.

Solution : Given,

Mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Formula used :

$\text{Moles of }CaO=\frac{\text{Mass of }CaO}}{\text{Molar mass of }CaO}$

Now put all the given values in this formula, we get the moles of calcium oxide.

$\text{Moles of }CaO=\frac{89.23g}{56g/mole}=1.593moles$

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

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How long does it take for light to travel??

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4 years ago

The value of K at constant temperature depends on the amounts of reactants and products that are mixed together initially. A lar

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Answer:

a) K = [ CO2(g) ]

⇒ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

Explanation:

a) CaCO3(s) ↔ CaO(s) + CO2(g)

⇒ K = [ CO2(g) ]

∴ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) H2(g) + F2(g) ↔ 2 HF(g)

⇒ K = [ HF(g) ] ² / [ F2(g) ] * [ H2(g) ]

⇒ Kp = PHF² / PF2 * PH2

for ideal gas:

PV = RTn

⇒ P = n/V RT = [ ] RT

⇒ Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same.

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

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3 years ago

Perform the following unit conversions:

Y_Kistochka [10]

Answer :

(a) The 60 feet of water is equal to 179344.2 Pa.

(b) The 220 psi is equal to $31680lbf/ft^2$

(c) The 120 torr is equal to 15998.6 Pa.

(d) The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The 1050 mm Hg is equal to $376.95lbf/ft^2$

Explanation :

(a) The conversion used from feet to pascal is:

$1\text{ feet}=2989.07Pa$

As we are given that 60 feet of water. Now we have to convert into Pa.

As, $1\text{ feet}=2989.07Pa$

So, $60\text{ feet}=\frac{60\text{ feet}}{1\text{ feet}}\times 2989.07Pa=179344.2Pa$

The 60 feet of water is equal to 179344.2 Pa.

(b) The conversion used from $psi$ to $lbf/ft^2$ is:

$1\text{ psi}=144lbf/ft^2$

As we are given that 220 psi. Now we have to convert into $lbf/ft^2$ .

As, $1\text{ psi}=144lbf/ft^2$

So, $220\text{ psi}=\frac{220\text{ psi}}{1\text{ psi}}\times 144lbf/ft^2=31680lbf/ft^2$

The 220 psi is equal to $31680lbf/ft^2$

(c) The conversion used from torr to pascal is:

$1\text{ torr}=133.322Pa$

As we are given that 120 torr. Now we have to convert into Pa.

As, $1\text{ torr}=133.322Pa$

So, $120\text{ torr}=\frac{120\text{ torr}}{1\text{ torr}}\times 133.322Pa=15998.6Pa$

The 120 torr is equal to 15998.6 Pa.

(d) 1.0 atm to inches of glycerin

Formula used : $P=\rho gh$

where,

P = pressure of glycerin = 1.0 atm = 101325 Pa

g = acceleration due to gravity = $9.8m/s^2$

$\rho$ = density of glycerin = $1260kg/m^3$

Now put all the given values in above formula, we get:

$101325Pa=(1260kg/m^3)\times (9.8m/s^2)\times h$

$h=8.206\frac{Pa.m^2s^2}{kg}=8.206m=323.07\text{ inches}$

Conversion used :

$1Pa=\frac{kg}{ms^2}\\\\1m=39.37inches$

The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The conversion used from $psi$ to $lbf/ft^2$ is:

$1\text{ mmHg}=0.359lbf/ft^2$

As we are given that 1050 mmHg. Now we have to convert into $lbf/ft^2$ .

As, $1\text{ mmHg}=0.359lbf/ft^2$

So, $1050\text{ mmHg}=\frac{1050\text{ mmHg}}{1\text{ mmHg}}\times 0.359lbf/ft^2=376.95lbf/ft^2$

The 1050 mm Hg is equal to $376.95lbf/ft^2$

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3 years ago