Answer:
sub-particle charge mass
protons +1 1
neutron 0 1
electron - 1 negligible
protons and neutrons are found in the nucleus
electrons in the shells orbiting the nucleus
Answer:
1.02 grams
Explanation:
The reaction between Na₃PO₄ and BaCl₂ is:
2Na₃PO₄(aq) + 3BaCl₂(aq) → Ba₃(PO₄)₂(s) + 6NaCl(aq)
We need to find the number of moles of Na₃PO₄ and BaCl₂:


Now, we need to find the limiting reactant:

We have that it is needed 0.0033 moles of Na₃PO₄ to react with BaCl₂ and we have 0.01 moles of Na₃PO₄, so the limiting reactant is BaCl₂.
The number of moles of Ba₃(PO₄)₂ is:

Finally, the mass of Ba₃(PO₄)₂ is:

Therefore, should be obtained 1.02 grams of the precipitate.
I hope it helps you!
Your answer is D. 8
16 = 2^4
72 = 2^3*3^2
So you'll choose 2^3 = 8
This answer would be heat capacity