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kakasveta [241]

3 years ago

8

A leap year happens every 4 years.There are 29 days in the month of February in a Leap year.A mathematician was born on 29th of

February 1792,and died on 20th of May 1861.How many times did he celebrate his birthday?

1 answer:

Veseljchak [2.6K]3 years ago

3 0

79years

Step-by-step explanation:

birth year minus the dearth yeah

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Consider a group of 1,000 newborn infants. One hundred (100) infants were born with serious birth defects, and 20 of these 100 d

kozerog [31]

Answer:

The prevalence of serious defects in this population at the time of birth is 10%.

Step-by-step explanation:

The prevalence of serious defects is the number of infants that were born with seriours birth defects divided by the total number of infants born.

In this problem, we have that:

There were 1000 newborn infants.

100 infants were born with serious birth defects.

Calculate the prevalence of serious defects in this population at the time of birth.

This is:

$P = \frac{10}{100} = 0.1$

The prevalence of serious defects in this population at the time of birth is 10%.

8 0

2 years ago

How to find the average squared distance between the points of the unit disk and the point (1,1)

ddd [48]

The unit disk can be parameterized by the function

$\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)$

where $0\le r\le 1$ and $0\le\theta\le2\pi$ . The squared distance between any point in this region $(x,y)=(r\cos\theta,r\sin\theta)$ and the point (1, 1) is

$(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2$
$=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)$
$=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2$
$=r^2-2r(\cos\theta-\sin\theta)+2$

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

$\dfrac{\displaystyle\iint_{x^2+y^2$
$=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}$
$=\dfrac{\frac{5\pi}2}\pi=\dfrac52$

5 0

2 years ago

The sum of 5 consecutive odd numbers is 145.

Anna007 [38]

Let x be the first odd integer. x + 2 the second x + 4 the third x + 6 the fourth x + 8 the fifth. add them up and you get 5x + 20 set 5x + 20 = 145 and solve for x. 5x=145-20 5x=125 x=25 answer=25,27,29,31,33

7 0

3 years ago

Read 2 more answers

An amusement park offers an entrance fee discount of 20% to children under 6 years of age and seniors 65 or older. What is the r

Temka [501]

Answer:

[0, 6) ∪ [65, ∞)

Step-by-step explanation:

Ages under 6 will be in the interval [0, 5], or in the interval [0, 6), as you may wish.

Ages 65 or older will be in the interval [65, ∞).

The union of these two intervals is ...

[0, 6) ∪ [65, ∞)

5 0

3 years ago

The sum of two consecutive integers is – 7. Find the numbers

Y_Kistochka [10]

$n,n+1$ - two consecutive integers

$n+n+1=-7\\2n=-8\\n=-4\\n+1=-3$

<u>-4 and -3</u>

7 0

3 years ago