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sergey [27]
3 years ago
7

A 3 cm tall object is placed 2 cm to the left of a converging lens that has a focal length with a magnitude of 4 cm. A diverging

lens with a focal length of magnitude 8 cm is placed 10 cm to the right of the first lens.
What is the magnification of the final image produced by these two lenses? Make sure you say whether it is bigger/smaller and upright/inverted.
Physics
1 answer:
kramer3 years ago
8 0

Answer:

the mangnafication of the final is smaller anbsgs sgs shs sgs vd

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9. Calculate the distance (in km) that Charlie runs if he maintains the average
Karo-lina-s [1.5K]

<u>Correct Question:</u>

Calculate the distance (in km) charlie runs if he maintains an average speed of 8 km/hr for 1 hour

<u>Answer:</u>

The total distance covered by Charlie is 8 km in 1 hour.

<u>Explanation:</u>

The average velocity as given in the question is,

v = 8 km/hr

Total time taken,

$t=1 hour

As we know the formula to evaluate the total distance d when the average velocity and time is given;

v=\frac{d}{t}

d=v \times t

d=8 \times 1

d=8 k m

Hence, the total distance covered by Charlie in 1 hour will be 8 km.

5 0
3 years ago
A 5 kg ball is sitting on top of a hill. It has a Potential Energy of 6000J. What is the height of the ball?​
natali 33 [55]

Explanation:

mass=5 kg

potential energy=6000j

height=?

Now

potential energy =m.g.h

or 6000=5*9.8*h

or 6000=49h

or 6000÷49=h

or h= 122.45m

6 0
3 years ago
What statement is true about a spring?
snow_tiger [21]
I think B is the most correct, because logically it's harder to bend a stiffer spring than it is to bend a softer one. Also, I don't think length comes into play. So B.
8 0
3 years ago
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4 0
4 years ago
A total Δν of 15 km/s is required to achieve an interplanetary mission. The proposed rocket has two stages. The first stage alon
AlexFokin [52]

Answer:

102000 kg

Explanation:

Given:

A total Δν = 15 km/s

first stage mass = 1000 tonnes

specific impulse of liquid rocket =  300 s

Mass flow rate of liquid fuel = 1500 kg/s

specific impulse of solid fuel = 250 s

Mass flow of solid fuel = 200 kg/s

First stage burn time = 1 minute = 1 × 60 seconds = 60 seconds

Now,

Mass flow of liquid fuel in 1 minute = Mass flow rate × Burn time

or

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Also,

Mass flow of solid fuel in 1 minute = Mass flow rate × Burn time

or

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Therefore,

The total jettisoned mass flow of the fuel in first stage

= 90000 kg +  12000 kg

= 102000 kg

3 0
3 years ago
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