Answer:
<u>Our beaches would be unprotected</u>
In the short-term, these artificial sand hills will be destroyed by the elements. Because sand dunes protect inland areas from swells, tides, and winds, they must be protected and defended like national treasures. ... The ocean and the wind can have an unpredictable, destructive force on coastal regions.
- surfertoday
Natural sand dunes play a vital role in protecting our beaches, coastline and coastal developments from coastal hazards such as erosion, coastal flooding and storm damage. Sand dunes protect our shorelines from coastal erosion and provide shelter from the wind and sea spray.
- Waikato Regional Council
Answer:
The correct answer to the following question will be "Particles".
Explanation:
- A particle seems to be a little component of something, it's little. When you're talking about a subatomic particle, that would be a structured user likely won't see because it's quite unbelievably thin, but it has a tiny mass as well as structural integrity. Such particles seem to be tinier than that of the particles or atoms.
- Such that the light which shines on the bit of metal could dissipate electrons, the particles seem to be more compatible with the light.
Answer:
1
only 4 is the significant figure
we take tailing zeroes as significant figures only in case of decimals
Explanation:
The given data is as follows.
n = 1 mol, 
Q = 1500 J, R = 8.314 J/mol k
(a) 
And, according to the first law of thermodynamics
And, in an isothermal process the change in internal energy of the gas is zero.
Hence, 0 = Q - W
or, W = Q
Expression for work done in an isothermal process is as follows.
W = 
As W = Q, Hence expression for Q will also be given as follows.
Q =
Now,
[/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]
= 
= nR ln 2
= 
= 5.76 J/K
Therefore, change in entropy is 5.76 J/K.
(b) As, Q =
= 
= nRT ln 2
T = 
= 
= 260.4 K
Therefore, temperature of the gas is 260.4 K.
