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Allushta [10]
2 years ago
10

240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an

Chemistry
1 answer:
ivolga24 [154]2 years ago
3 0
The answer for this would be 69.6
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What is the difference between weight and mass?
Rashid [163]

Answer: it's easy just think about it:

Explanation:

weight: the weight of an object is the force acting on the object due to gravity.

mass: Mass is the amount of matter or substance that makes up an object.

in total: The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it.

Happy to help!

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2 years ago
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A gas can holds 2.9 gal of gasoline. what is the quantity in cubic centimeters
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3 0
2 years ago
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pashok25 [27]

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A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128
QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

DH_{lead}=-DH_{water}

Now, by stating the heat capacity definition:

m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\

Solving for the equilibrium temperature:

T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

Best regards.

5 0
2 years ago
Scoring scheme: 3-3-2-1 using the ion concentration values in cells #3 & #5 in the expression, ecell#5 - ecell#3 = -(0.0257/
nexus9112 [7]
I made a fake account and everything but still no answer. Brainly done got me [email protected] up
3 0
3 years ago
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