Epithelial tissues often form the lining of organs and secrete substances such as digestive enzymes.

A boy takes hold of a rope to pull a wagon (m = 50 kg) on a surface with a static coefficient of friction μS = 0.25. Calculate t

vivado [14]

Answer:

The force that would be applied on the rope just to start moving the wagon is 122 N

Explanation:

Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move can be calculated using equation 1.

F = μ x mg .............................. 1

where F is the frictional force;

μ is the coefficient of friction ( μs, in this case, static friction);

m is mass of the object and;

g is the acceleration due to gravity( a constant equal to 9.81 m/ $s^{2}$ )

from the equation we are provide with;

μs = 0.25

m = 50 kg

g = 9.81 m/ $s^{2}$

F =?

Using equation 1

F = 0.25 x 50 kg x 9.81 m/ $s^{2}$

F = 122.63 N

Therefore a force of 122 N must be applied to the rope just to start the wagon.

6 0

3 years ago

Read 2 more answers

A mechanic uses a hydraulic car jack to lift the front end of a car to change the oil. The jack used exerts 8,915 N of force fro

Vaselesa [24]

Answer:

63.05 cm²

Explanation:

We use Pascals law to find the answer.

The law says that in an incomprehensible , non-viscous fluid the pressure applied will transmit through out the fluid without a change.

So, Pressure on larger piston = pressure on smaller piston.

$\frac{444}{3.14} = \frac{8915}{A}$

A ≅ 63.05 cm²

3 0

2 years ago

A rigid object has a mass of 18kg and a radius of gyration of 0.3m. It is initially rotating clockwise about a fixed axis at its

ElenaW [278]

Answer:

:0 i dont know

Explanation:

4 0

2 years ago

The eagle drops the trout a height of 6.1 m the fish travels 7.9 m horizontaly before hitting the water what is the velocity of

Semenov [28]

The velocity of the eagle is 7.0 m/s

Explanation:

The motion of the fish is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction, where the horizontal velocity of the fish is equal to the horizontal velocity of the eagle

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion, using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where:

s = 6.1 m is the vertical displacement of the fish

u = 0 is the initial vertical velocity of the fish

$a=g=9.8 m/s^2$ is the acceleration of gravity

t is the time

Solving for t, we find the time of flight of the fish:

$t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(6.1)}{9.8}}=1.12 s$

Now we know that during this time, the fish travels a horizontal distance of

x = 7.9 m

Therefore, the horizontal velocity of the fish is

$v_x = \frac{x}{t}=\frac{7.9}{1.12}=7.0 m/s$

And therefore, this is the initial velocity of the eagle.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0

3 years ago

How long must a flute be in order to have a fundamental frequency of 262 Hz (this frequency corresponds to middle C on the evenl

spin [16.1K]

Answer:

L=0.654 m

Explanation:

Concepts and Principles

1- The speed of sound in air is expressed as a function of the temperature of air as follows:

v=(331 m/s)√(1+T_C/273°C) (1)

where 331 m/s is the speed of sound in air at temperature 0°C and Tc is the temperature of air in Celsius.

Standing Wave Patterns in Pipes:

A pipe open at both ends can have standing wave patterns with resonant frequencies:

f=v/λ=nv/2L n=1,2,3.........

where v is the speed of sound in air.

Given Data

f_1 (fundamental frequency of the flute) = 262 Hz

T (temperature of the air) = 20°C

The flute is open at both ends.

Required Data

We are asked to determine the length of the tube.

Solution

The speed of sound in air at temperature T = 20°C is found from Equation (1):

v=(331 m/s)√(1+T_C/273°C)

=342.91 m/s

The fundamental frequency of the flute is found by substituting n = 1 into Equation (2):

f=v/2L

Solve for L:

L=v/2f_1

L=0.654 m

7 0

2 years ago