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LuckyWell [14K]
2 years ago
15

Which of these is the easiest mineral identification property to use when you want to know whether you have pyrite or actual gol

d?
a. heft
b. luster
c. streak
d. magnetism
Physics
1 answer:
Makovka662 [10]2 years ago
5 0

Answer:

c. streak

Explanation:

Pyrite is a mineral that looks like gold but actually is iron disulfide.

Pyrite and gold have comparable luster.

Pyrite and gold have different tones of yellow. This can be determined by their streak. Streak is the powdered form of a mineral. A streak of mineral can be found just by rubbing the mineral on a rough surface and comparing the colors.

Pyrite is diamagnetic which is not a strong form of magnetism. Gold is also diamagnetic

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The equipotential surfaces surrounding a point charge are concentric spheres with the charge at the center. If the electric pote
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Answer:

1.06 m

Explanation:

Since the charge is at the centre of two concentric spheres, we use the formula for electric potential due to a point charge. V = kq/r. Let r₁ be the radius of the sphere with potential, V₁ = 200 V and  r₂ be the radius of the sphere with potential, V₂ = 82.0 V. From V = kq/r, r = kq/V. So that r₁ = kq/V₁ and r₂ = kq/V₂. The magnitude of the difference r₁ - r₂ is the distance between the two surfaces. q the charge equals 1.63 × 10⁻⁸ C

r₂ - r₁ = kq/V₂ - kq/V₁ = kq(1/V₂ - 1/V₁) = 1.63 × 10⁻⁸ × 9 × 10⁹ (1/82 -1/200) m =  1.63 × 10⁻⁸ × 9 × 10⁹ (0.0122 - 0.005) = 1.63 × 10⁻⁸ × 9 × 10⁹(0.0072) m = 1.06 m

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8 0
2 years ago
. A 2.0-m wire carries a current of 15 A directed along the positive x axis in a region where the magnetic field is uniform and
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Answer:

The resulting magnetic force on the wire is -1.2kN

Explanation:

The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is

F = I (L*B)

Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)

L x B = \left[\begin{array}{ccc}i&j&k\\2&0&0\\30&-40&0\end{array}\right] = (0, 0, -80)

we can now solve

F = I (L x B) = I (-80)

F = -1200 kmN

F = -1200 kN * 10⁻³

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