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hodyreva [135]
3 years ago
7

What is the temperature of the star in the illustration?

Physics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:a star’s brightness or luminosity depends on the star’s surface temperature and size.

Explanation:

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3. Ultraviolet can kill these. <br><br>8words and 2nd letter starts with an A​
Karo-lina-s [1.5K]

Answer:

Bacteria

Explanation:

UV kills bacteria and its 8 letters

7 0
3 years ago
A current-carrying wire is bent into a circular loop of radius R and lies in an xy plane. A uniform external magnetic field B in
Ilya [14]

Answer:

 F = 2π I R B

Explanation:

The magnetic force is described by the equation.

      F = q v x B = i L  x B

Where i is the current, L is a vector that points in the direction of the current (length) and B is the magnetic field.

This equation can be used in scalar form and the direction of the force found by the right hand ruler, the thumb goes in the direction of L, the fingers extended in the direction of B and the palm of the hand indicates the direction of the force if the load is positive

     F = i L B sin θ

In this case the wire is in the xy plane and the z-axis field whereby they are perpendicular, θ = 90º and sin 90 = 1

     F = i L B

The loop length is

    L = 2π R

    F = i 2π R B

    F = 2π I R B

The force is in the loop

8 0
3 years ago
The density of atmosphere on a certain planet is found to decrease as altitude increases what is the type of relationship betwee
8_murik_8 [283]
? Is there options ??????
6 0
3 years ago
A bag of sugar weighs 2 kg on earth. What should it weigh in newtons on the moon, where the free-fall acceleration is 1/6 that o
Elis [28]
<span> Weight = mass x acceleration
Earths acceleration is 9.8 m/s*2
1 kg = 2.2 lbs, so 2.0 lbs x 1 kg/2.2 lbs = 0.91 kg
The bag would have a weight of 9.8 x 0.91 = 8.9 N

1. 8.9 x 1/6 = 1.5 N

2. 8.9 x 2.64 = 23.5 N

The mass of the bag at all three locations is 0.91 kg. Mass does not change, the different locations only change its weight. </span>
5 0
3 years ago
An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s
ad-work [718]

Answer:

a

 \theta  =  0.0022 rad

b

 I  =  0.000304 I_o

Explanation:

From the question we are told that  

   The  wavelength of the light is \lambda  = 550 \ nm  =  550 *10^{-9} \ m

    The  distance of the slit separation is  d = 0.500 \ mm = 5.0 *10^{-4} \ m

 

Generally the condition for two slit interference  is  

     dsin \theta =  m \lambda

Where m is the order which is given from the question as  m = 2

=>    \theta  =  sin ^{-1} [\frac{m \lambda}{d} ]

 substituting values  

      \theta  =  0.0022 rad

Now on the second question  

   The distance of separation of the slit is  

       d =  0.300 \ mm  =  3.0 *10^{-4} \ m

The  intensity at the  the angular position in part "a" is mathematically evaluated as

      I  =  I_o  [\frac{sin \beta}{\beta} ]^2

Where  \beta is mathematically evaluated as

       \beta  =  \frac{\pi *  d  *  sin(\theta )}{\lambda }

  substituting values

     \beta  =  \frac{3.142  *  3*10^{-4}  *  sin(0.0022 )}{550 *10^{-9} }

    \beta  = 0.06581

So the intensity is  

    I  =  I_o  [\frac{sin (0.06581)}{0.06581} ]^2

   I  =  0.000304 I_o

3 0
3 years ago
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