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4 years ago

Let c = 10. Drag the expression into the box that makes the comparison true

Mathematics

1 answer:

Virty [35]4 years ago

7 0

Answer: the answer is c^2 / 10

Hope this helps :p

Step-by-step explanation:

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a number cubes tolled 450 times. the number 3 comes up 67 times. what I's the theoretical probability of rolling a 3 ? WRITE YOU

zvonat [6]

Assuming number cube has 6 sides

probablity is (desiredoutcomes)/(total possible ouctomes)

since it is 450 times
total possible outcomes=450

experimiental probablity is the one actaully obtained by doing it
theoretical is the predicted amount

so theoretical probablity of rolling a 3 is 1 number out of 6 or 1/6 or 75 times out o 450 times

experimiental is the actaull one so67 out of 450 or 67/450

theoretical is 1/6 or 75/450
experimental is 67/450

4 0

3 years ago

Divide. Write your answer as a fraction in simplest form. −10 2/7÷(−4 4/11)= NEED ASAP

Otrada [13]

Answer:

33/14

hope this helps :)

8 0

3 years ago

Could someone please help me:) I am stick and I am not sure what to do

Delicious77 [7]

Answer:

Part 5.1.1:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin 2A = \frac{\sqrt{15}}{8}$

Part 5.1.1

Recall that:

$\displaystyle \sin^2 \theta + \cos^2 \theta = 1$

Let θ = 2A. Hence:

$\displaystyle \sin ^2 2A + \cos ^2 2A = 1$

Square the original equation:

$\displaystyle \sin^2 2A = \frac{15}{64}$

Hence:

$\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1$

Subtract:

$\displaystyle \cos ^2 2A = \frac{49}{64}$

Take the square root of both sides:

$\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}$

Since 0° ≤ 2A ≤ 90°, cos(2A) must be positive. Hence:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2

Recall that:

$\displaystyle \begin{aligned} \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &= 1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}$

We can use the third form. Substitute:

$\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1$

Solve for cosine:

$\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}$

In conclusion:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

(Note that since 0° ≤ 2A ≤ 90°, 0° ≤ A ≤ 45°. Hence, cos(A) must be positive.)

4 0

3 years ago

Can someone help me?

Ivenika [448]

Answer:

Step-by-step explanation:

Hope this helps!

3 0

3 years ago

Read 2 more answers

WILL GIBE BRAINLEST

professor190 [17]

Answer:

Step-by-step explanation:

The answer choices don’t make sense. The volume of a cylinder of height 45mm and radius 5mm = π5²*45 = 1125π mm³.

Three of the answer choices are larger than 1125π.

:::::

volume of one cone = πr²h* ⅓

Volume of cylinder section = πr²h

Total volume = πr²h*⅔ + πr²h = πr²h*5/3 = π5²*15*5/3 = 625π

7 0

3 years ago