Answer:
a) 2-bromopyrrole
Explanation:
Our options for this questions are:
a) 2-bromopyrrole
b) 2,3-dibromopyrrole
c) N-bromopyrrole
d) 3-bromopyrrole
To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.
The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the 
and 
. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).
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Given the mass of 
=25.6 g
The molar mass of =390.35g/mol
Converting mass of to moles:
Converting mol to mol S:
Converting mol S to atoms of S using Avogadro's number:
1 mol = 
Answer: The amount of carbon-14 left after 10 years is 25 g
Explanation:
Formula used :
where,
a = amount of reactant left after n-half lives = ?
= Initial amount of the reactant = 100 g
n = number of half lives =
Putting values in above equation, we get:
Therefore, the amount of carbon-14 left after 10 years is 25 g
