What are the parts of a chromosome

Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257

Inessa [10]

Answer:

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

4 0

4 years ago

1.24 grams of magnesium phosphate tribasic dissolved in 1 L of lemon juice. What is the Ksp of the magnesium phosphate tribasic

vivado [14]

<u>Answer:</u> The solubility product of magnesium phosphate tribasic is $2.52\times 10^{-10}$

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of magnesium phosphate = 1.24 g

Molar mass of magnesium phosphate = 262.85 g/mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.24g}{262.85g/mol\times 1}\\\\\text{Molarity of solution}=4.72\times 10^{-3}M$

The equation for the ionization of the magnesium phosphate is given as:

$Mg_3(PO_4)_2\leftrightharpoons 3Mg^{2+}+2PO_4^{3-}$

Expression for the solubility product of $Mg_3(PO_4)_2$ will be:

$K_{sp}=[Mg^{2+}]^3[PO_4^{3-}]^2$

We are given:

$[Mg^{2+}]=(3\times 4.72\times 10^{-3})=1.416\times 10^{-2}M$

$[PO_4^{3-}]=(2\times 4.72\times 10^{-3})=9.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(1.416\times 10^{-2})^3\times (9.44\times 10^{-3})^2=2.52\times 10^{-10}$

Hence, the solubility product of magnesium phosphate tribasic is $2.52\times 10^{-10}$

4 0

3 years ago

. Using at least 3 to 4 complete content related sentences, explain how the compressed gas in an aerosol can forces paint out of

Sophie [7]

Erosols aren't aerosols at all. No, really, let's be clear about this. An aerosol is really the cloud<span> of </span>liquid and gas<span>that comes out of an aerosol can, not the can itself. In fact, to be strictly correct about it, an aerosol is a fine mist of liquid, or lots of solid particles, widely and evenly dispersed throughout a gas. So clouds, fog, and steam from your kettle are all examples of aerosols, because they're made up of </span>water<span> droplets dispersed through a much bigger volume of air. Smoke is an aerosol too, though unlike those other examples (which are liquids dispersed in gases) it's made up of </span>solid<span> particles of unburned carbon mixed through a cloud of warm, rising air. Even </span>candles<span> make aerosols: the smoky steam swirling above a candle flame consists of soot and water vapor dispersed through hot air.

HOPE THIS HELP
</span>

3 0

3 years ago

Read 2 more answers

The ionization energy of silver is 731 kJ/mol. Is light with a wavelength of 415 nm sufficient to remove an electron from a silv

sineoko [7]

The energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

<h3>Energy and wavelength of light</h3>

The energy and wavelength of light are related by the formula given below:

Energy = hc/λ
where, E = energy
h = Planck's constant
c = velocity of light
λ = wavelength of light

<h3>Calculating the energy of the light</h3>

From the data provided:

h = 6.63 × 10^-34 Js
c = 3.0 × 10^8 m/s
λ = 415 nm = 4.15 × 10^-7 m

E = (6.63 × 10^-34 × 3.0 × 10^8 m/s)/4.15 × 10^-7 m

E = 4.79 × 10^-19 J

Energy of light is 4.79 × 10^-19 J

Compared with the ionization energy of silver, the energy of the light is far less.

Therefore, the energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

Learn more about about ionization energy and energy of light at: brainly.com/question/14596067

8 0

3 years ago

3 ejemplos de sublimacion<br>

Vanyuwa [196]

Uno:

El dióxido de Carson (CO2)

7 0

3 years ago