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4 years ago

Which change will always result in an increase in the gravitational force between two objects?

Physics

1 answer:

ira [324]4 years ago

7 0

Answer:

Increasing the masses of the objects and decreasing the distance between the objects

Explanation:

The force of gravity pulls every body with mass towards the center of the earth.This is the force of attraction between two bodies as a result of their masses.Gravity force is directly proportional to the mass of a body.A body with more mass experiences a greater force of gravity.Additionlay, when the distance between two bodies decreases, the gravitational force increases.

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Which theory proposed by Galileo is considered a “big mistake of his life”? What did the theory state, and why was it a “big mis

e-lub [12.9K]

The erroneous theory of Galileo was that tides were a result of the earth's what he called the inconsistent revolution around the sun. He was right about the most important thing of the earth revolving around the sun but didn't realize that the moon (and sun) exert a gravitational pull on the earth's oceans and cause the diurnal tides to occur.

7 0

3 years ago

Read 2 more answers

A billiards ball B rests on a horizontal surface and is struck by another billiards ball A of the same mass m = 0.2 kg. Ball A i

SOVA2 [1]

Answer:

v1 = 15.90 m/s

v2 = 8.46 m/s

mechanical energy before collision = 32.4 J

mechanical energy after collision = 32.433 J

Explanation:

given data

mass m = 0.2 kg

speed = 18 m/s

angle = 28°

to find out

final velocity and mechanical energy both before and after the collision

solution

we know that conservation of momentum remain same so in x direction

mv = mv1 cosθ + mv2cosθ

put here value

0.2(18) = 0.2 v1 cos(28) + 0.2 v2 cos(90-28)

3.6 = 0.1765 V1 + 0.09389 v2 ................1

and

in y axis

mv = mv1 sinθ - mv2sinθ

0 = 0.2 v1 sin28 - 0.2 v2 sin(90-28)

0 = 0.09389 v1 - 0.1768 v2 .......................2

from equation 1 and 2

v1 = 15.90 m/s

v2 = 8.46 m/s

mechanical energy before collision = 1/2 mv1² + 1/2 mv2²

mechanical energy before collision = 1/2 (0.2)(18)² + 0

mechanical energy before collision = 32.4 J

and

mechanical energy after collision = 1/2 (0.2)(15.90)² + 1/2 (0.2)(8.46)²

mechanical energy after collision = 32.433 J

7 0

3 years ago

A curent-carrying 2.0-cm long segment of wire is inside a long solenoid adius - 40 cm - 800 turns/m, current - 50 mA). The wire

klasskru [66]

Answer:

The value is $F_{max} = 12 \muN$

Explanation:

From the question we are told that

The length is $l = 2.0 \ cm = 0.02 \ m$

The radius of the the solenoid is $r =40 \ cm$

The number of turns per meter is $N = 800 \ turns / m$

The current through the solenoid is $I = 50 \ mA = 50*10^{-3} \ A$

The current through the segment is $I_s = 12 \ A$

Generally the magnetic force is mathematically represented as

$F = B * I_s l sin(\theta)$

At maximum $\theta = 90^o$

$F_{max} = B * I_s l$

Here B is the magnetic field is mathematically represented as

$B = \mu_o * N * I$

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$B = 4\pi * 10^{-7} * 800 *50*10^{-3}$

=> $B = 5.0272 *10^{-5} \ T$

$F_{max} = 5.0272 *10^{-5} * 12 * 0.02$

$F_{max} = 1.2 *10^{-5}$

$F_{max} = 12 \muN$

4 0

3 years ago

A shiny new sports car sits in a parking lot of a car dealership. above is a cargo plane, flying horizontally at 46 m/s. at the

dybincka [34]

First calculate the time it would take for the crate to fall using the formula:

h = v0 t + 0.5 g t^2

110 m = 0 + 0.5 (9.8 m/s^2) t^2

t = 4.74 s

The crate is also moving at 46 m/s on with respect to the horizontal surface, therefore distance covered is:

d = (46 m/s) * 4.74 s

d = 217.95 m

The crate would fall 217.95 m from the tail of the car.

6 0

3 years ago

A sample of an ideal gas is heated, and its kelvin temperature doubles. What happens to the average speed of the molecules in th

BabaBlast [244]

A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of $\sqrt{2}$

The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.

Root mean square speed is a statistical measurement of speed.

The root mean square speed can be calculated as : V1 : $\sqrt{3 R T / Mo}$

if temperature becomes double

let T1 is initial temperature

So , T2 = 2 * T1

now ,

Root mean square speed will be (V2) = $\sqrt{(3 R (2T)) / Mo}$

= $\sqrt{2}$ * $\sqrt{3 R T / Mo}$

= $\sqrt{2}$ V1

Thus when temperature becomes double, the root mean square speed increases by a factor of $\sqrt{2}$

To learn more about root mean square velocity here

brainly.com/question/13751940

#SPJ4

3 0

1 year ago