Answer:
v_h = 9 m/s
Explanation:
given,
mass of the rocket = 1500 kg
accelerates = 10 m/s²
time = 4 s
one fragment is twice as massive as the other.
maximum height reached by the lighter fragment = 530 m
now,
using equation of motion to calculate the velocity
initial velocity of rocket,u = 0 m/s
v = u + a t
v = at.......(1)
total mass of the rocket
M = m + m'
m' is the heavier particle mass.
m' = 2 m (from the statement given in the question)
M = 3 m
m = M/3
now, again using equation of motion to calculate the initial velocity of the lighter particle.
v² = u² + 2 a s
0² = u² + 2 g h
u = √2gh.....(2)
now,
using conservation of momentum,





2 v_h = 18
v_h = 9 m/s
speed of the heavy fragment is equal to 9 m/s
The correct answer is C. The potential at the center of the sphere is the same as
the potential at the surface
The valence electrons of metals are weakly attracted to the parent nuclei, so the electrons break free and float. The moving electrons form a electron <u>negative</u> blanket that binds the atomic <u>positive</u> nuclei together, forming a metallic bond.
So the answers are <u>{ Negative }</u> and <u>{ Positive }.</u>
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Answer:
c, 280,000J
Explanation:
You should use the equation KE (Kinetic Energy) = 
m = 2500
v = 15
KE = 
KE = 281250 Joules.
This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.
KE = 280,000 J
Answer:
Explanation:
There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.
momentum of first piece = .320 kg x 2 m/s
= 0.64 kg m/s along x -axis.
momentum of second piece = .355 kg x 1.5 m/s
= 0.5325 kg m/s along y- axis .
Let the velocity of third piece be v and it is making angle of θ with x -axis .
Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ
vertical component of its velocity = .100 kg x v sinθ = .1 v sinθ
For making total momentum in the plane zero
.1 v cosθ = 0.64 kg m/s
.1 v sinθ = 0.5325 kg m/s
Dividing
Tanθ = .5325 / .64 = .83
θ = 40⁰.
The angle will be actually 180 + 40 = 220 ⁰ from positive x -axis.