Based on the number of people who chose the other fruits, the percentage of people who chose pears was <u>25%. </u>
<h3>Number of people who chose pears </h3>
= Number of participants - Number who chose apples - Number who chose oranges
= 60 - 28 - 17
= 15 people
<h3>Percentage who chose pears </h3>
= Number of people who chose pears / Total number of people x 100%
= 15 / 60 x 100%
= 25%
In conclusion, 25% chose pears.
Find out more on percentages at brainly.com/question/13516343.
Answer:
D. y=30x
Step-by-step explanation:
So x represents like say if he mowed 3 yards.
y=30(3)
Then y would equal 90
Answer:
Step-by-step explanation:
Hello!
X: Cholesterol level of a woman aged 30-39. (mg/dl)
This variable has an approximately normal distribution with mean μ= 190.14 mg/dl
1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:
P(Z≥z₀)= 0.093
-*or*-
P(Z≤z₀)= 0.907
Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:
P(Z≤z₀)= 0.907
Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:
z₀= 1.323
2.
Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:
Z= (X- μ)/δ ~N(0;1)
Z= (X- μ)/δ
Z*δ= X- μ
δ=(X- μ)/Z
δ=(240-190.14)/1.323
δ= 37.687 ≅ 37.7 mg/dl
I hope it helps!
Hey This Is The Answer I Got
(x-1)/16=6/12
16*6=12(x-1)
96=12x-12
12x=84
x=7
Hoped I Helped
