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2 years ago

C=27+10h where c= cost in dollars and h= number of hours rented

Mathematics

1 answer:

gavmur [86]2 years ago

3 0

Answer:

that help

Step-by-step explanation:

10h+27+−27=c+−27

10h=c−27

10h10=c−2710

h=110c+−2710

Answer:

h=110c+−2710

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2 years ago

Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semest

sineoko [7]

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0.91824 = 91.824% probability that more than 3 students will have their automobiles stolen during the current semester.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

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e = 2.71828 is the Euler number

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Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester.

This means that $\mu = 7$

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This is:

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.00091$

$P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.00638$

$P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.02234$

$P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.05213$

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$

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.08176 = 0.91824$

0.91824 = 91.824% probability that more than 3 students will have their automobiles stolen during the current semester.

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2 years ago

C=27+10h where c= cost in dollars and h= number of hours rented ​

C=27+10h where c= cost in dollars and h= number of hours rented